Klaas Vantournhout wrote:
> Hi, Somehow I can't figure this one out.
>
> I have an integer variable N and this N reflects the amount of nested
> for loops. I mean
>
> if N = 1, the I have
>
> for (int i1 = ....) {
> <code>
> }
>
> if N = 2, I have
>
> for (int i1 = ...)
> for (int i2 = ...) {
> <code>
> }
>
> ...
>
> if N = n I must have
>
> for (int i1 = ...)
> ...
> for (int in = ...) {
> <code>
> }
>
>
> Is there a way to program this disregarding the value of N?
>
> thanks
It depends on the value of the upper bound and lower bound obviously
In case all are the same, (upperlower)^n will do.
For instance:
for (i=0; i<10;i++)
for (j=0; j<10;j++)
<code>
is the same as
for (i=0; i<100; i++)
<code>
100=(10  0) ^ 2
jacob
