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What is the effect of the following code?

char Ch;

Ch = '7';

printf("%d\n", Ch);

The choices available are:

a. It will cause an error

b. It will print out the computer's internal code for the character '7'

c. It will print out the character '7'

d. It will print out the character whose internal code is 7


"Daniel Antonson" <> wrote in message
news:QoidnehXbYGD9lrfRVn-...
> What is the effect of the following code?
>
> char Ch;
>
> Ch = '7';
>
> printf("%d\n", Ch);
>
>

In article <-_2dnTq1Ad8c8VrfRVn->,
Daniel Antonson <> wrote:
>"Daniel Antonson" <> wrote in message
>news:QoidnehXbYGD9lrfRVn-...
>> What is the effect of the following code?

>> char Ch;

>> Ch = '7';

>> printf("%d\n", Ch);


>The choices available are:

>a. It will cause an error

Yup. You can't call a function at file scope, so the code will
not compile as-is.
--
"Who Leads?" / "The men who must... driven men, compelled men."
"Freak men."
"You're all freaks, sir. But you always have been freaks.
Life is a freak. That's its hope and glory." -- Alfred Bester, TSMD

On Sun, 03 Jul 2005 00:41:37 -0400, Daniel Antonson wrote:

> The choices available are:
>
> a. It will cause an error
>
> b. It will print out the computer's internal code for the character '7'
>
> c. It will print out the character '7'
>
> d. It will print out the character whose internal code is 7
>
>
> "Daniel Antonson" <> wrote in message
> news:QoidnehXbYGD9lrfRVn-...
>> What is the effect of the following code?
>>
>> char Ch;
>>
>> Ch = '7';
>>
>> printf("%d\n", Ch);
>>
>>

Which one did you choose?

--Mac

Answer will be 'b'
It will print out the computer's internal code for the character '7'

In article <. com>,
sandeep <> wrote:
:Answer will be 'b'

What answer will be 'b'? You didn't quote any establishing context.

:It will print out the computer's internal code for the character '7'

Obviously you didn't try it.

$ gcc -std=c89 -pedantic -o seven seven.c
seven.c:3: error: conflicting types for `Ch'
seven.c:1: error: previous declaration of `Ch'
seven.c:3: error: ISO C forbids data definition with no type or storage class
seven.c:5: error: parse error before string constant
seven.c:5: warning: conflicting types for built-in function `printf'
seven.c:5: error: ISO C forbids data definition with no type or storage class

$ gcc -std=c99 -pedantic -o seven seven.c
seven.c:3: warning: type defaults to `int' in declaration of `Ch'
seven.c:3: error: conflicting types for `Ch'
seven.c:1: error: previous declaration of `Ch'
seven.c:3: error: ISO C forbids data definition with no type or storage class
seven.c:5: error: parse error before string constant
seven.c:5: warning: type defaults to `int' in declaration of `printf'
seven.c:5: warning: conflicting types for built-in function `printf'
seven.c:5: error: ISO C forbids data definition with no type or storage class

$ : SGI IRIX below

$ cc -o seven -fullwarn seven.c
cc-1077 cc: ERROR File = seven.c, Line = 3
The indicated declaration has no storage class or type specifier.

Ch = '7';
^

cc-1143 cc: ERROR File = seven.c, Line = 3
Declaration is incompatible with "char Ch" (declared at line 1).

Ch = '7';
^

cc-1079 cc: ERROR File = seven.c, Line = 5
A type specifier is expected.

printf("%d\n", Ch);
^

cc-1079 cc: ERROR File = seven.c, Line = 5
A type specifier is expected.

printf("%d\n", Ch);
^

cc-1077 cc: WARNING File = seven.c, Line = 5
The indicated declaration has no storage class or type specifier.

printf("%d\n", Ch);
^

4 errors detected in the compilation of "seven.c".

--
Any sufficiently advanced bug is indistinguishable from a feature.
-- Rich Kulawiec

Daniel Antonson wrote:
> What is the effect of the following code?
>
> char Ch;
>
> Ch = '7';
>
> printf("%d\n", Ch);

idk, seems obvious to me that it prints the ascii value of '7'. is it a
question to tell newbies in C from others?

Walter Roberson wrote:
> In article <. com>,
> sandeep <> wrote:
> :Answer will be 'b'
>
> What answer will be 'b'? You didn't quote any establishing context.
>
> :It will print out the computer's internal code for the character '7'
>
> Obviously you didn't try it.
What made u think that i didn,t tried that
I tried and i got "55" as the internal value of '7'.
Which is also the ASCII value for "7".
Now i got it correct and you might be having some problem with your
compiler or you missed something.
anyways be careful in future.
>
> $ gcc -std=c89 -pedantic -o seven seven.c
> seven.c:3: error: conflicting types for `Ch'
> seven.c:1: error: previous declaration of `Ch'
> seven.c:3: error: ISO C forbids data definition with no type or storage class
> seven.c:5: error: parse error before string constant
> seven.c:5: warning: conflicting types for built-in function `printf'
> seven.c:5: error: ISO C forbids data definition with no type or storage class
>
> $ gcc -std=c99 -pedantic -o seven seven.c
> seven.c:3: warning: type defaults to `int' in declaration of `Ch'
> seven.c:3: error: conflicting types for `Ch'
> seven.c:1: error: previous declaration of `Ch'
> seven.c:3: error: ISO C forbids data definition with no type or storage class
> seven.c:5: error: parse error before string constant
> seven.c:5: warning: type defaults to `int' in declaration of `printf'
> seven.c:5: warning: conflicting types for built-in function `printf'
> seven.c:5: error: ISO C forbids data definition with no type or storage class
>
> $ : SGI IRIX below
>
> $ cc -o seven -fullwarn seven.c
> cc-1077 cc: ERROR File = seven.c, Line = 3
> The indicated declaration has no storage class or type specifier.
>
> Ch = '7';
> ^
>
> cc-1143 cc: ERROR File = seven.c, Line = 3
> Declaration is incompatible with "char Ch" (declared at line 1).
>
> Ch = '7';
> ^
>
> cc-1079 cc: ERROR File = seven.c, Line = 5
> A type specifier is expected.
>
> printf("%d\n", Ch);
> ^
>
> cc-1079 cc: ERROR File = seven.c, Line = 5
> A type specifier is expected.
>
> printf("%d\n", Ch);
> ^
>
> cc-1077 cc: WARNING File = seven.c, Line = 5
> The indicated declaration has no storage class or type specifier.
>
> printf("%d\n", Ch);
> ^
>
> 4 errors detected in the compilation of "seven.c".
>
> --
> Any sufficiently advanced bug is indistinguishable from a feature.
> -- Rich Kulawiec

As it will print the ASCII value of '7' which is 55

sandeep wrote:
> Answer will be 'b'
> It will print out the computer's internal code for the character '7'
As it will print the ASCII value of '7' which is 55