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I've been trying to figure out a way to parse the following:

192.168.0.7;username;password;database

I'm stumped as to how to do that. Should I look for the first occurance
of the ';', cut out position x through the position of the delimiter by 1,
move that string to another string and repeat?

-Alex

AlexB wrote:
> I've been trying to figure out a way to parse the following:
>
> 192.168.0.7;username;password;database
>
> I'm stumped as to how to do that.

Parsing IP addresses has been done to death. Search the archives
of clc.

> Should I look for the first occurance of the ';', cut out
> position x through the position of the delimiter by 1,
> move that string to another string and repeat?

int ip[4];
char username[256];
char password[256];
char database[256];
char ignore;

int r = sscanf(the_string,
"%3d.%3d.%3d.%3d;%255[^;];%255[^;];%255[^;]%c",
&ip[0], &ip[1], &ip[2], &ip[3],
&username, &password, &database, &ignore);

if (r == 7)
{
printf("%3d.%3d.%3d.%3d;%255[^;];%255[^;];%255[^;]%c",
ip[0], ip[1], ip[2], ip[3],
username, password, database);
}

--
Peter

AlexB <> wrote:
> I've been trying to figure out a way to parse the following:

> 192.168.0.7;username;password;database

> I'm stumped as to how to do that. Should I look for the first occurance
> of the ';', cut out position x through the position of the delimiter by 1,
> move that string to another string and repeat?

What about something like the following? Depends of course a bit on
what you exactly mean by "parsing" etc...

#include <stdio.h>

int main( void )
{
const char *sl = "192.168.0.7;username;password;database";
char ip[ 16 ];
char un[ 100 ];
char pw[ 100 ];
char db[ 100 ];

sscanf( sl, "%15[^;];%99[^;];%99[^;];%99s", ip, un, pw, db );
printf( "%s - %s - %s - %s\n", ip, un, pw, db );
return 0;
}

And, of course, there's the strtok() function, but you need to know
what you are doing if you use it.

Regards, Jens
--
\ Jens Thoms Toerring ___
\__________________________ http://www.toerring.de

On Thu, 17 Mar 2005 18:01:50 -0800, Peter Nilsson wrote:

> AlexB wrote:
>> I've been trying to figure out a way to parse the following:
>>
>> 192.168.0.7;username;password;database
>>
>> I'm stumped as to how to do that.
>
>

Jens & Peter, thanks! Never thought of that suggestion.. I started going
with strncpy source,dest,length and then parsing it like that..but yours
sounds alot better.

Thanks guys!!

-Alex

Peter Nilsson wrote:
> printf("%3d.%3d.%3d.%3d;%255[^;];%255[^;];%255[^;]%c",
> ip[0], ip[1], ip[2], ip[3],
> username, password, database);

Make that...

"%d.%d.%d.%d;%s;%s;%s"

--
Peter

"AlexB" <> wrote in message
> I've been trying to figure out a way to parse the following:
>
> 192.168.0.7;username;password;database
>
> I'm stumped as to how to do that. Should I look for the first
occurance
> of the ';', cut out position x through the position of the delimiter
by 1,
> move that string to another string and repeat?

The proposed sscanf() solutions isn't very robust.

1. Do you only need to consider IPv4 addresses (what about IPv6)?
2. isn't ';' a legal character in passwords? If so, why not???
3. consider using a more robust TLV scheme, instead of this comma
separated list.


--
Tor <torust AT online DOT no>

On Fri, 18 Mar 2005 14:38:11 +0100, Tor Rustad wrote:

> "AlexB" <> wrote in message
>> I've been trying to figure out a way to parse the following:
>>
>> 192.168.0.7;username;password;database
>>
>> I'm stumped as to how to do that. Should I look for the first
> occurance
>> of the ';', cut out position x through the position of the delimiter
> by 1,
>> move that string to another string and repeat?
>
> The proposed sscanf() solutions isn't very robust.
>
> 1. Do you only need to consider IPv4 addresses (what about IPv6)?
> 2. isn't ';' a legal character in passwords? If so, why not???
> 3. consider using a more robust TLV scheme, instead of this comma
> separated list.

yes just IPv4.. its basically for me.. I'm writing a little piece of
software that connects to a MySQL db and stores info in it.
You know..I tried the following and it didnt work..

instead of a fgets I used:
fscanf( temp, "%15[^;];%99[^;];%99[^;];%99s", &hostname, &username,
&password, &database);

all variables were parsed except the hostname..
so I did a fgets into temp and then
sscanf( temp, "%15[^;];%99[^;];%99[^;];%99s", &hostname, &username,
&password, &database);

and it worked.. weird.

-Alex

On Sat, 19 Mar 2005 16:36:12 +0000, AlexB wrote:

> instead of a fgets I used:
> fscanf( temp, "%15[^;];%99[^;];%99[^;];%99s", &hostname, &username,
> &password, &database);

little typo.. where temp is, I have fp.