http://www.velocityreviews.com/forums/(E-Mail Removed) wrote:

> I have a digital camera with a CCD of 2/3 and an 8mm lens attached. Is

> the following formula correct to determine FOV?

>

> FOV=2arctan(.5*width of frame*distance to frame)

>

> SECOND QUESTION, how would I determine the field of view if the camera

> is not rotating around the origin, but rather on a boom that extends

> out from the origin?

>

> Thanks

> Jordan

>
One mistake- the second times (*) sign is actually a division (2

atan(0.5*width/EFL), where efl is distance from lens node to image.

With a rectangular format, there are actually THREE fields of view.

The horizontal, vertical, and corner to corner (conical) fields of view

can each be computed. What you have shown is the horizontal FOV if you

mean the 36mm dimension of the format in 35mm equivalent. The width of

35 mm format is of course in the vertical dimension of the format.

So say you normally shoot landscape format. Then the width of the

format is the greater of the two dimensions and the formula you show is

for horizontal FOV (with the operator as division instead of multiplication.