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#1 |
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I need to make a collection wherein i can have a key value pair and the
sorting happens in alphabetical order of values. also i want that after the initial insert of values if i add or remove any value then the collection should be sorted again in alphabetical order. - i cant use arraylist because it doesnt have a key value pair. - i cant use a hashmap because when i iterate the values i get them in a random order whereas i want them in alphabetical order. - TreeMap does the sorting in order of keys. - LinkedHashMap does the sorting in order of insertion. so for the initial insert it will be fine but when i add and remove values it will not give me the alphabetical order. would appreciate some help on this thanks shikha Shikha |
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#2 |
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Shikha wrote:
> I need to make a collection wherein i can have a key value pair and the > sorting happens in alphabetical order of values. also i want that after > the initial insert of values if i add or remove any value then the > collection should be sorted again in alphabetical order. > - i cant use arraylist because it doesnt have a key value pair. > - i cant use a hashmap because when i iterate the values i get them in > a random order whereas i want them in alphabetical order. > - TreeMap does the sorting in order of keys. > - LinkedHashMap does the sorting in order of insertion. so for the > initial insert it will be fine > but when i add and remove values it will not give me the alphabetical > order. Try just putting the (key,value) pairs in an ordinary HashMap. When you want to visit all the values (or all the pairs) in order by value, use .values() to extract the values (or .entrySet() to extract the pairs), sort them, and traverse the sorted data instead of the original Map. That might not be suitable for all situations, but works for many. If it's not the right answer for your predicament, you'll need to describe your purposes more fully. -- Eric Sosman lid Eric Sosman |
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#3 |
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> Try just putting the (key,value) pairs in an ordinary HashMap. > When you want to visit all the values (or all the pairs) in order > by value, use .values() to extract the values (or .entrySet() to > extract the pairs), sort them, and traverse the sorted data instead > of the original Map. you mean to say that i should get the values and put them in an arraylist and then access the values from the arraylist instead of getting them from the map ? > That might not be suitable for all situations, but works for > many. If it's not the right answer for your predicament, you'll > need to describe your purposes more fully. what you suggested should i work. it would have been good if i were able to directly put the values in some collection which does a sorting of values. i want to take a list of vendors from the database alongwith their ids and store them in a collection. then i want to keep adding and removing values from this collection based on some user inputs. Thanks shikha Shikha |
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#4 |
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Posts: n/a
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> > Try just putting the (key,value) pairs in an ordinary HashMap. > > When you want to visit all the values (or all the pairs) in order > > by value, use .values() to extract the values (or .entrySet() to > > extract the pairs), sort them, and traverse the sorted data instead > > of the original Map. > > you mean to say that i should get the values and put them in an > arraylist and then access the values from the arraylist instead of > getting them from the map ? > Eric, I was about to try this out but i realised that this wouldnt work. Because i need to populate the values from a Map. the reason being that when the user selects a particular value i need to pick the corresponding key for the value. so if i populate the values from arraylist i wouldnt be able to get the corresponding id. any other suggestions ? thanks shikha Shikha |
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#5 |
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Posts: n/a
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Shikha wrote On 08/16/06 09:25,: >>> Try just putting the (key,value) pairs in an ordinary HashMap. >>>When you want to visit all the values (or all the pairs) in order >>>by value, use .values() to extract the values (or .entrySet() to >>>extract the pairs), sort them, and traverse the sorted data instead >>>of the original Map. >> >>you mean to say that i should get the values and put them in an >>arraylist and then access the values from the arraylist instead of >>getting them from the map ? >> > > Eric, I was about to try this out but i realised that this wouldnt > work. Because i need to populate the values from a Map. the reason > being that when the user selects a particular value i need to pick the > corresponding key for the value. so if i populate the values from > arraylist i wouldnt be able to get the corresponding id. If you need the (key,value) pairs sorted by value, not just the values themselves, use theMap.entrySet() to get them: it gives you a Collection of Map.Entry objects, each representing one (key,value) pair. Sort that Collection of pairs using a Comparator that looks at the values. -- Eric Sosman |
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#6 |
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Posts: n/a
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Eric Sosman <> writes:
>If you need the (key,value) pairs sorted by value, not >just the values themselves, use theMap.entrySet() to get >them: it gives you a Collection of Map.Entry objects, each >representing one (key,value) pair. Sort that Collection of >pairs using a Comparator that looks at the values. When a value is inserted, it could be inserted into both collections, keeping their respective invariants: So the sorted collection will stay sorted (insertation sort). Just inserting a single value into the correct position should be faster than to sort anew. Shifting all following values could be faster if a linked list is used. However: All this is very low-level. So it might be best to encapsulate the whole decision and implement it in the most convenient way at first. Then, when the first copies of the program are sold and it turns out that this implementation really is too slow, it still can be optimized for version 1.1. Stefan Ram |
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