«

How can I return:

".666"

from float:

"0.666"

This is what I have so far:

>>> "%.6f" % x

Thanks Everyone,
Derek Basch

Derek Basch wrote:
> How can I return:
>
> ".666"
>
> from float:
>
> "0.666"
>
> This is what I have so far:
>
>>>> "%.6f" % x
>
> Thanks Everyone,
> Derek Basch
>

This works but I'm not entirely sure I know what you are
trying to accomplish.

("%.3f" % x)[1:]


-Larry Bates

Ahh yes you have to put parenthases around the string formatting to
remove the integer using indexes. Thanks, that's just what I needed!

Derek Basch

"Derek Basch" <> writes:
> Ahh yes you have to put parenthases around the string formatting to
> remove the integer using indexes. Thanks, that's just what I needed!

I think it's better to remove leading zeros explicitly:

('%.3x' % x).lstrip('0')

On 24/03/2006 6:44 AM, Larry Bates wrote:
> Derek Basch wrote:
>
>>How can I return:
>>
>>".666"
>>
>>from float:
>>
>>"0.666"
>>
>>This is what I have so far:
>>
>>
>>>>>"%.6f" % x
>>
>>Thanks Everyone,
>>Derek Basch
>>
>
>
> This works but I'm not entirely sure I know what you are
> trying to accomplish.
>
> ("%.3f" % x)[1:]
>

>>> x = 12345.666; ("%.3f" % x)[1:]
'2345.666'
>>>

I'm sure of neither what the OP is trying to accomplish nor what Larry's
definition of "works" is

Perhaps the condition abs(x) < 1.0 is implied ...

John Machin wrote:
> On 24/03/2006 6:44 AM, Larry Bates wrote:
>> Derek Basch wrote:
>>
>>> How can I return:
>>>
>>> ".666"
>>>
>>> from float:
>>>
>>> "0.666"
>>>
>>> This is what I have so far:
>>>
>>>
>>>>>> "%.6f" % x
>>>
>>> Thanks Everyone,
>>> Derek Basch
>>>
>>
>>
>> This works but I'm not entirely sure I know what you are
>> trying to accomplish.
>>
>> ("%.3f" % x)[1:]
>>
>
>>>> x = 12345.666; ("%.3f" % x)[1:]
> '2345.666'
>>>>
>
> I'm sure of neither what the OP is trying to accomplish nor what Larry's
> definition of "works" is
>
> Perhaps the condition abs(x) < 1.0 is implied ...

For the example given, my code works. With so little information
the only thing I could do is answer the specific question and
caveat it that I don't know "exactly" what OP is trying to accomplish.
By the OPs response to my post, it was what he was looking for.
But I agree it is very much an edge-case question.

-Larry Bates

With that terse description and the subject line I would interpret the
OP like so:

>>> print re.sub(".*\.",".","0.666")
..666
>>> print re.sub(".*\.",".","123.666")
..666

On 2006-03-23, Arne Ludwig <> wrote:
> With that terse description and the subject line I would interpret the
> OP like so:
>
>>>> print re.sub(".*\.",".","0.666")
> .666
>>>> print re.sub(".*\.",".","123.666")
> .666

Or if you're allergic to regular expressions:

>>> print "." + "0.666".split(".")[-1]
..666
>>> print "." + "123.666".split(".")[-1]
..666
>>>



--
Grant Edwards grante Yow! Yow! It's a hole
at all the way to downtown
visi.com Burbank!