On May 28, 2005, at 2:52 PM, Lorn wrote:

> Yes, that would get rid of the decimals... but it wouldn't get rid of

> the extraneous precision. Unfortunately, the precision out to the ten

> thousandth is noise... I don't need to round it either as the numbers

> are artifacts of an integer to float conversion. Basically, I need to

> know how many decimal places there are and then make the necessary

> deletions before I can normalize by adding zeros, multiplying, etc.

>

> Thanks for your suggestion, though.
for s in numbers:

decimal_index = s.find('.')

decimal_places = len(s) - decimal_index - 1

Anything wrong with this? (it will mess up if there isn't a decimal

but you can fix that if you want)

-- Elliot Temple

http://www.curi.us/
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