"jfdutcher1958" <> writes:
> Python returns this message:
>
> InvalidURL: nonnumeric port: '//www.a2webhosting.com:2083/frontend/x2'
>
> in reponse to the call below ....but the port number looks
> numeric ???
>
> ************************************************** *************
> import sys, httplib
> showlines = 56
> try:
> servername, filename = sys.argv[1:] # cmdline args?
> except:
> servername, filename
> = 'https://www.a2webhosting.com:2083/frontend/x2', '/index.html'
>
> print servername, filename
You've forgotten a line (the one which throws the error you've given).
But, I believe your problem is 'https://www....' is parsed as a
server

ort pair: the server is https, and the port is //www..., which
of course is invalid.
I presume you're doing httplib.HTTPConnection(servername) (or
HTTPSConnection). You can't use a URL there. Usage from the docs is
like this:
>>> h1 = httplib.HTTPConnection('www.cwi.nl')
>>> h2 = httplib.HTTPConnection('www.cwi.nl:80')
>>> h3 = httplib.HTTPConnection('www.cwi.nl', 80)
Depending on what you're doing, you might be better off using the
urllib or urllib2 modules.
--
|>|\/|<
/--------------------------------------------------------------------------\
|David M. Cooke
|cookedm(at)physics(dot)mcmaster(dot)ca