«

The following does not work although it seems like something you should be
able to do.

def someFunction(option=Constants.DEFAULT_VALUE):

Thanks,

V

Vineet Jain wrote:

> The following does not work although it seems like something you should be
> able to do.
>
> def someFunction(option=Constants.DEFAULT_VALUE):

Please post the actual error traceback you are getting, and a
better description of "does not work". Your problem could be
just about anything at this point...

-Peter

On Sun, 4 Apr 2004 19:26:30 -0400, Vineet Jain wrote:
> The following does not work although it seems like something you
> should be able to do.
>
> def someFunction(option=Constants.DEFAULT_VALUE):

That's not a question.

Is there something that isn't behaving as you expect? If so, please
explain what you expect, and what you're actually experiencing.

--
\ "I took a course in speed waiting. Now I can wait an hour in |
`\ only ten minutes." -- Steven Wright |
_o__) |
Ben Finney <http://bignose.squidly.org/>

In article <mailman.341.1081121191.20120.python->,
"Vineet Jain" <> wrote:
>The following does not work although it seems like something you should be
>able to do.
>
>def someFunction(option=Constants.DEFAULT_VALUE):

Certainly seems like it. What's it doing to make you say
it's not working?

Regards. Mel.

"Vineet Jain" <> wrote in
news:mailman.341.1081121191.20120.python-:

> The following does not work although it seems like something you
> should be able to do.
>
> def someFunction(option=Constants.DEFAULT_VALUE):
>
Do you mean in a context like this?

>>> class Const:
.... someVal=255
.... otherVal=0
....
>>> Const.someVal
255
>>> someVal=255
>>> someVal
255
>>> def blip(Const.someVal):
File "<stdin>", line 1
def blip(Const.someVal):
^
SyntaxError: invalid syntax
>>> def blip(someVal):
.... (no syntax error)


I've wondered about that, too.


--
rzed

rzed wrote:

> "Vineet Jain" <> wrote in
> news:mailman.341.1081121191.20120.python-:
>
>> The following does not work although it seems like something you
>> should be able to do.
>>
>> def someFunction(option=Constants.DEFAULT_VALUE):
>>
> Do you mean in a context like this?
>
>>>> class Const:
> ... someVal=255
> ... otherVal=0
> ...
>>>> Const.someVal
> 255
>>>> someVal=255
>>>> someVal
> 255
>>>> def blip(Const.someVal):
> File "<stdin>", line 1
> def blip(Const.someVal):
> ^
> SyntaxError: invalid syntax
>>>> def blip(someVal):
> ... (no syntax error)
>
>
> I've wondered about that, too.

Stop wondering then:

>>> class Constants:
.... DEFAULT_VALUE = 42
....
>>> def someFunction(option=Constants.DEFAULT_VALUE):
.... print "option =", option
....
>>> someFunction(1)
option = 1
>>> someFunction()
option = 42
>>> Constants.DEFAULT_VALUE = "another value"
>>> someFunction()
option = 42
>>> Constants = None
>>> someFunction()
option = 42

Here Constants might also be a module. The only constraint is that
Constants.DEFAULT_VALUE is bound when the function is defined, not when
it's called.

Peter

rzed wrote:
> "Vineet Jain" <> wrote in
> news:mailman.341.1081121191.20120.python-:
>
>
>>The following does not work although it seems like something you
>>should be able to do.
>>
>>def someFunction(option=Constants.DEFAULT_VALUE):
>>
>
> Do you mean in a context like this?
>
>
>>>>class Const:
>
> ... someVal=255
> ... otherVal=0
> ...
>
>>>>Const.someVal
>
> 255
>
>>>>someVal=255
>>>>someVal
>
> 255
>
>>>>def blip(Const.someVal):
>
> File "<stdin>", line 1
> def blip(Const.someVal):
> ^
> SyntaxError: invalid syntax
>
>>>>def blip(someVal):
>
> ... (no syntax error)
>
>
> I've wondered about that, too.
>
>

i checked this out, and i think its the name you were using:

Const

i tried this, and it works fine

>class mconst:
> testval = 255

>def testme(test = mconst.testval)
> print test

>print testme()

255


if this is what you wanted dont use the word const for the class

CU
Marco

Marco Bartel wrote:

> rzed wrote:
>
>> "Vineet Jain" <> wrote in
>> news:mailman.341.1081121191.20120.python-:
>>
>>> The following does not work although it seems like something you
>>> should be able to do.
>>>
>>> def someFunction(option=Constants.DEFAULT_VALUE):
>>>

I suspect what the OP wants is to evaluate "Constants.DEFAULT_VALUE"
at function call time, not function definition time.
Indeed, something like the following does not work:

def someFunction(option=Constants.DEFAULT_VALUE):
print 'the option was', option

class Constants:
DEFAULT_VALUE = 13

someFunction()

In fact:
class Constants:
DEFAULT_VALUE = 13

def someFunction(option=Constants.DEFAULT_VALUE):
print 'the option was', option

Constants.DEFAULT_VALUE = 7 # get luckier

someFunction()

prints 13, not the possibly desired 7.



>> Do you mean in a context like this?
>> class Const:
>> someVal=255
>> otherVal=0
>>
>> def blip(Const.someVal):
Should be:
def blip(test=Const.someVal):
>
> i checked this out, and i think its the name you were using:
> Const
Nope, it is the missing arg name.

--
-Scott David Daniels

Scott David Daniels <> wrote in
news::

> Marco Bartel wrote:
>
>> rzed wrote:
>>
[...]
>>> Do you mean in a context like this?
>>> class Const:
>>> someVal=255
>>> otherVal=0
>>>
>>> def blip(Const.someVal):
> Should be:
> def blip(test=Const.someVal):
>>
>> i checked this out, and i think its the name you were using:
>> Const
> Nope, it is the missing arg name.
>

Well, not so much that as an incorrectly formed parameter name. I
can legally do this:
def blip( someVal ):
...

but not this:
def blip( x.someVal ):
=> SyntaxError aimed at the dot.

Since there is no argname to assign a value to, "Const.someVal" is
taken as an identifier for a passed-in parameter. But it seems
(sensibly enough) that an identifier can't contain a '.' character,
which evidently is reserved for a qualifier separator (or some such
term) in that context.

--
rzed