«

I need:
dict = {2002 : {'Jan': {1 : 'num1', 2: 'num2', 3 : 'num3'},
{'Feb': {1 : 'num4', 2: 'num5', 3 : 'num6'} } }
2003 : {'Jan': {1 : 'num7', 2: 'num8', 3 : 'num9'} } }

How to do it programmatically?
In Perl I would do something like:

while ($line = <>) {
if ($line =~ /^---\s+\w+\s+(\w+)\s+(\d*)\s+(\d+)\d+)\d+)\s+(\d+) \s+---$/) {
($month,$date,$hour,$minute,$sec,$year) = ($1,$2,$3,$4,$5,$6);
$statistics->{$year}->{$month}->{$date} += $sec;
}
}

But how to do it in Python without catching 'KeyError' exception or
iterating over some nested loops. How to do it elegantly?

--
WBR, VS

In article <>, Vlad Sirenko <> wrote:
>I need:
>dict = {2002 : {'Jan': {1 : 'num1', 2: 'num2', 3 : 'num3'},
> {'Feb': {1 : 'num4', 2: 'num5', 3 : 'num6'} } }
> 2003 : {'Jan': {1 : 'num7', 2: 'num8', 3 : 'num9'} } }
>
>How to do it programmatically?
>In Perl I would do something like:
>
>while ($line = <>) {
> if ($line =~ /^---\s+\w+\s+(\w+)\s+(\d*)\s+(\d+)\d+)\d+)\s+(\d+) \s+---$/) {
> ($month,$date,$hour,$minute,$sec,$year) = ($1,$2,$3,$4,$5,$6);
> $statistics->{$year}->{$month}->{$date} += $sec;
> }
>}
>
>But how to do it in Python without catching 'KeyError' exception or
>iterating over some nested loops. How to do it elegantly?

You don't need nested loops, but you do need multiple statements:

tmp_year = stats.setdefault(year, {})
tmp_month = tmp_year.setdefault(month, {})
tmp_month[date] = tmp_month.setdefault(date, 0) + sec
--
Aahz () <*> http://www.pythoncraft.com/

This is Python. We don't care much about theory, except where it intersects
with useful practice. --Aahz

"Aahz" <> schrieb im Newsbeitrag
news:bhc9bh$lp9$...
> In article <>, Vlad Sirenko <>
wrote:
> >I need:
> >dict = {2002 : {'Jan': {1 : 'num1', 2: 'num2', 3 : 'num3'},
> > {'Feb': {1 : 'num4', 2: 'num5', 3 : 'num6'} } }
> > 2003 : {'Jan': {1 : 'num7', 2: 'num8', 3 : 'num9'} } }
> >
> >How to do it programmatically?
> >In Perl I would do something like:
> >
> >while ($line = <>) {
> > if ($line =~
/^---\s+\w+\s+(\w+)\s+(\d*)\s+(\d+)\d+)\d+)\s+(\d+) \s+---$/) {
> > ($month,$date,$hour,$minute,$sec,$year) = ($1,$2,$3,$4,$5,$6);
> > $statistics->{$year}->{$month}->{$date} += $sec;
> > }
> >}


This is what I love Perl for!
BTW: Do you really mean += ?
This does nor match yourt example, neither seems to make much sense. Perhaps
a misconception?

> >
> >But how to do it in Python without catching 'KeyError' exception or
> >iterating over some nested loops. How to do it elegantly?
>
> You don't need nested loops, but you do need multiple statements:
>
> tmp_year = stats.setdefault(year, {})
> tmp_month = tmp_year.setdefault(month, {})
> tmp_month[date] = tmp_month.setdefault(date, 0) + sec

*I* think this is less readable than the Python expression!
Note that *get* and *setdefault* are most powerful operations on mapping
types
once you get used to them, that is...

Kindly
Michael P

> --
> Aahz () <*>
http://www.pythoncraft.com/
>
> This is Python. We don't care much about theory, except where it
intersects
> with useful practice. --Aahz