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I need a piece of code that takes a string like this string1 =
"aaa/bbb/ccc/dd" and extracts a string containting the character after
the last "/"

So for this example the result would be "dd"

like this:
for i=0; string1.right(i) != '/'; i++

result = string1.mid(i, string1.length())

but in python.

| I need a piece of code that takes a string like this
| string1 = "aaa/bbb/ccc/dd" and extracts a string containting
| the character after the last "/"
|
| So for this example the result would be "dd"
| ...

lamar_air ...

Here is one way ...


>>> str_in = 'aaa/bbb/ccc/dd'
>>>
>>> list_in = str_in.split( '/' )
>>>
>>> last_element = list_in[ -1 ]
>>>
>>> print last_element
dd
>>>


--
Cousin Stanley
Human Being
Phoenix, Arizona

On Tue, Jul 15, 2003 at 01:58:09PM -0700, Cousin Stanley wrote:
> | I need a piece of code that takes a string like this
> | string1 = "aaa/bbb/ccc/dd" and extracts a string containting
> | the character after the last "/"
> |
> | So for this example the result would be "dd"
> | ...
>
> lamar_air ...
>
> Here is one way ...
>
>
> >>> str_in = 'aaa/bbb/ccc/dd'
> >>>
> >>> list_in = str_in.split( '/' )
> >>>
> >>> last_element = list_in[ -1 ]
> >>>
> >>> print last_element
> dd
> >>>
>
>
> --
> Cousin Stanley
> Human Being
> Phoenix, Arizona
>

In Unix,

>>> os.path.basename("aaa/bbb/ccc")
'ccc'

Inyeol

John Hunter wrote:

>>>>>>"lamar" == lamar air <> writes:
>
>
> lamar> I need a piece of code that takes a string like this
> lamar> string1 = "aaa/bbb/ccc/dd" and extracts a string
> lamar> containting the character after the last "/"
>
> One good way to do this is to split the string on the '/' character,
> which creates a list of strings
>
> >>> string1 = "aaa/bbb/ccc/dd"
> >>> parts = string1.split('/')
> >>> parts
> ['aaa', 'bbb', 'ccc', 'dd']
>
> Now you just want to get the last element of this list; python allows
> you to index with -1 to get the last element, -2 to get the second to
> last, etc...
>
> >>> parts[-1]
> 'dd'
>
> JDH
>

While is is perfectly acceptable, you might want to consider another
solution if it is *path names* you are manipulating:

>>> import os
>>> os.path.split("aaa/bbb/ccc/dd")
('aaa/bbb/ccc', 'dd')
>>> os.path.split("aaa/bbb/ccc/dd")[1]
'dd'


because this will work correctly on other platforms too when the
path separator is not '/'.

--Irmen de JOng

I know a few people replied to this already, but here's one additional
possibility. If the data in string1 is a file path for your platform,
then you can use the os.path module.

>>> import os.path
>>> os.path.split("aaa/bbb/ccc/dd")
('aaa/bbb/cc', 'dd')
>>> os.path.splitext("filename.ext")
('filename', '.ext')

The other suggestions will of course work, but if you data is a file
path, then using the os.path module should be a more portable solution.

Brandon



"lamar_air" <> wrote in message
news: om...
> I need a piece of code that takes a string like this string1 =
> "aaa/bbb/ccc/dd" and extracts a string containting the character after
> the last "/"
>
> So for this example the result would be "dd"
>
> like this:
> for i=0; string1.right(i) != '/'; i++
>
> result = string1.mid(i, string1.length())
>
> but in python.

On 15 Jul 2003 13:23:09 -0700, (lamar_air) wrote:

>I need a piece of code that takes a string like this string1 =
>"aaa/bbb/ccc/dd" and extracts a string containting the character after
>the last "/"
>
>So for this example the result would be "dd"
>
>like this:
>for i=0; string1.right(i) != '/'; i++
>
>result = string1.mid(i, string1.length())
>
>but in python.

Others have posted the split() solutions.
You could also search backward in Python:

>>> s = "aaa/bbb/ccc/dd"
>>> s[s.rfind('/')+1:]
'dd'
>>> s='no_slashes'
>>> s[s.rfind('/')+1:]
'no_slashes'

Regards,
Bengt Richter

On 15 Jul 2003 19:51:56 -0700, (Vinoo Vasudevan) wrote:

> (lamar_air) wrote in message news:<. com>...
>> I need a piece of code that takes a string like this string1 =
>> "aaa/bbb/ccc/dd" and extracts a string containting the character after
>> the last "/"
>>
>> So for this example the result would be "dd"
>>
>> like this:
>> for i=0; string1.right(i) != '/'; i++
>>
>> result = string1.mid(i, string1.length())
>>
>> but in python.
>
>How about this:
>string1 = 'aaa/bbb/ccc/dd'
>result = string1[string1.rfind('/')+1:]
>
>Hope it's helpful,
Sorry Vinoo, for some reason your post did not show up for me before I posted
the same solution, even though your post is dated much before mine.
I guess it has to do with delays in news servers forwarding and such.

Regards,
Bengt Richter