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Hi,dear all:

I have the following question. If I want to initialize an array using
braces, is there a way that I can define them and give the initial
value in different lines, like:

int X[5];
X[5] = {0,0,1,2,9};

But this gives me error message. I know "int X[5] = {0,0,1,2,9};"
works.
I really want to do this because this is a public array and will be
used by many Subroutines.

Thanks!

Sincerely,
Trevor

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Trevor Qi wrote:

> Hi,dear all:
>
> I have the following question. If I want to initialize an array using
> braces, is there a way that I can define them and give the initial
> value in different lines, like:
>
> int X[5];
> X[5] = {0,0,1,2,9};

Not unless you use a typographical break rather than a statement break.

You'd have to do something like

int X[5]
= {0,0,1,2,9};

Otherwise, what you want to do is not possible, and your code sample is
incorrect.

> But this gives me error message. I know "int X[5] = {0,0,1,2,9};"
> works.
> I really want to do this because this is a public array and will be
> used by many Subroutines.
>
> Thanks!
>
> Sincerely,
> Trevor


- --

Lew Pitcher, IT Consultant, Enterprise Application Architecture
Enterprise Technology Solutions, TD Bank Financial Group

(Opinions expressed here are my own, not my employer's)
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Trevor Qi wrote:
> Hi,dear all:
>
> I have the following question. If I want to initialize an array using
> braces, is there a way that I can define them and give the initial
> value in different lines, like:
>
> int X[5];
> X[5] = {0,0,1,2,9};
>
As I know, there isn't, even in C99.

Explain any reaseon why you want to do it in two lines.

vir

(Trevor Qi) wrote in
news: om:

> Hi,dear all:
>
> I have the following question. If I want to initialize an array using
> braces, is there a way that I can define them and give the initial
> value in different lines, like:
>
> int X[5];
> X[5] = {0,0,1,2,9};
>
> But this gives me error message. I know "int X[5] = {0,0,1,2,9};"
> works.
> I really want to do this because this is a public array and will be
> used by many Subroutines.

Then no, you cannot. You could do something silly like:

x[0] = 0, x[1] = 0, x[2] = 1, x[3] = 2, x[4] = 9;

but that's probably not something that will scale too well. If x[] is
file-scoped you could create a function level array and the memcpy() it.
E.g.

#include <string.h>

int x[5];

int main(void)
{
int private_x[] = { 0, 0, 1, 2, 9 };

memcpy(x, private_x, sizeof x);

return 0;
}

--
- Mark ->
--

Trevor Qi wrote:
> Hi,dear all:
>
> I have the following question. If I want to initialize an array using
> braces, is there a way that I can define them and give the initial
> value in different lines, like:
>
> int X[5];
> X[5] = {0,0,1,2,9};
>
> But this gives me error message. I know "int X[5] = {0,0,1,2,9};"
> works.
> I really want to do this because this is a public array and will be
> used by many Subroutines.

It sounds to me like this is what you want (tested with gcc):

In a header named 'array.h', include the line:

extern int X[5];

Then, create another file (perhaps: array.c), include:

int X[5] = { 0, 0, 1, 2, 9 };

Then either #include 'array.h' in each file that uses this array or use:

extern int X[5];

in any lexical scope that uses the array.

Tim

In 'comp.lang.c', (Trevor Qi) wrote:

> Hi,dear all:
>
> I have the following question. If I want to initialize an array using
> braces, is there a way that I can define them and give the initial
> value in different lines, like:
>
> int X[5];
> X[5] = {0,0,1,2,9};
>
> But this gives me error message. I know "int X[5] = {0,0,1,2,9};"
> works.
> I really want to do this because this is a public array and will be
> used by many Subroutines.

If it is a read-only data, you can define it

/* in a unique compile unit */
static int const X[] = {0,0,1,2,9};

or

/* shared constant */
int const X[];

with this declaration:
extern int const X[] = {0,0,1,2,9};

Example :

#include <stdio.h>

extern int const X[] = {0,0,1,2,9};

int const X[];

int main (void)
{
int i;

for (i = 0; i < sizeof X / sizeof *X; i++)
{
printf ("X[%d] = %d\n", i, X[i]);
}
return 0;
}

D:\CLC\T\TREVOR>bc
X[0] = 0
X[1] = 0
X[2] = 1
X[3] = 2
X[4] = 9

Or

/* const.c */
#include "const.h"

int const X[];

#ifndef H_ED_CONST_20040514223101
#define H_ED_CONST_20040514223101

/* const.h */
extern int const X[] = {0,0,1,2,9};

#endif /* guard */

/* Guards added by GUARD (c) ED 2000-2003 May 09 2004 Ver. 1.6 */

/* main.c */
#include <stdio.h>
#include "const.h"

int main (void)
{
int i;

for (i = 0; i < sizeof X / sizeof *X; i++)
{
printf ("X[%d] = %d\n", i, X[i]);
}
return 0;
}

--
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The C-language FAQ: http://www.eskimo.com/~scs/C-faq/top.html
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FAQ de f.c.l.c : http://www.isty-info.uvsq.fr/~rumeau/fclc/

Trevor Qi wrote:

> Hi,dear all:
>
> I have the following question. If I want to initialize an array using
> braces, is there a way that I can define them and give the initial
> value in different lines, like:
>
> int X[5];
> X[5] = {0,0,1,2,9};
>
> But this gives me error message. I know "int X[5] = {0,0,1,2,9};"
> works.
> I really want to do this because this is a public array and will be
> used by many Subroutines.

Assignment of arrays is not part of C. To copy arrays at a go, use
memmove() or memcpy().

I have given another answer in the code below, but it will *not* work
with C89 compilers, which means it will not work with most actually
existing compilers. Even when it _does_ work, it may not be the best
approach.

int main(void)
{
int *X;
X = (int [5]){ 0, 0, 1, 2, 9}; /* make the pointer (not array) X
point to an anonymous array */
return 0;
}

On Fri, 14 May 2004 22:00:16 +0400, Victor Nazarov wrote:

> Trevor Qi wrote:
>> Hi,dear all:
>>
>> I have the following question. If I want to initialize an array using
>> braces, is there a way that I can define them and give the initial
>> value in different lines, like:
>>
>> int X[5];
>> X[5] = {0,0,1,2,9};
>>
> As I know, there isn't, even in C99.

Then you know wrong: C99 permits compound literals.

Like so:

int *X;
X = (int [5]) {0,0,1,2,9};

Not exactly the same, but damned close.

>
> Explain any reaseon why you want to do it in two lines.

A lot of other languages permit much the same thing.

>
> vir

--
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"Makes hackers smile" makes hackers smile.

August Derleth <> writes:

> On Fri, 14 May 2004 22:00:16 +0400, Victor Nazarov wrote:
>
>> Trevor Qi wrote:
>>> Hi,dear all:
>>>
>>> I have the following question. If I want to initialize an array using
>>> braces, is there a way that I can define them and give the initial
>>> value in different lines, like:
>>>
>>> int X[5];
>>> X[5] = {0,0,1,2,9};
>>>
>> As I know, there isn't, even in C99.
>
> Then you know wrong: C99 permits compound literals.
>
> Like so:
>
> int *X;
> X = (int [5]) {0,0,1,2,9};
>
> Not exactly the same, but damned close.

Even closer:
int X[5];
memcpy(X, (const int[5]) {0, 0, 1, 2, 9}, sizeof X);
--
"I hope, some day, to learn to read.
It seems to be even harder than writing."
--Richard Heathfield

Martin Ambuhl <> wrote:
> Trevor Qi wrote:
> > I have the following question. If I want to initialize an array using
> > braces, is there a way that I can define them and give the initial
> > value in different lines, like:
> >
> > int X[5];
> > X[5] = {0,0,1,2,9};
> >
> > But this gives me error message.
>
> Assignment of arrays is not part of C. To copy arrays at a go, use
> memmove() or memcpy().
>
> int *X;
> X = (int [5]){ 0, 0, 1, 2, 9};

Is it completely portable to go:

int X[5];
memcpy(X, (int []){ 0, 0, 1, 2, 9}, 5 * sizeof(int));

(I imagine that a trap representation might be generated after copying
some of the bytes of an int)