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unnumbered interfaces in routing information ?

 
 
Evgeny Vainerman
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      01-15-2004
Let's assume two devices are connected by p2p link via unnumbered
interfaces:

|=====| |=====|
| | Ser0 | |
| A 0-------------------0 B 0-----Network 10.0.3.0/24
| | Ser0 | |
|=====| |=====|

Both interfaces are unnumbered and each one shares the IP address with
the device's loopback.

A's loppback is 10.0.1.1/24
B's loopback is 10.0.2.1/24

How does routing table od router A look like ?

S 10.0.3.0 [1/1] via 10.0.2.1, Serial0 ?

Would I see network 10.0.2.0/24 as a connected ?

C 10.0.2.0/24 is directly connected, Serial0 ?

Thanks, Evgeny.
 
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Helmut Ulrich
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      01-15-2004
It depends on your configuration. If you do the following configuration
on router A
ip route 10.0.3.0 255.255.255.0 serial0
and using HDLC as encapsulation on the serial line

then the routing table will look like this:

C 10.0.2.0/24 is directly connected, loopback0
S 10.0.3.0/24 is directly connected, Hssi0/0

If you use PPP as encapsulation on your serial lien the router A will
learn the IP address of the neighbor router as a host address. The
routing table will look like this:

C 10.0.2.0/24 is directly connected, loopback0
S 10.0.3.0/24 is directly connected, serial0/0
S 10.0.2.1/32 is directly connected, serial0/0


Evgeny Vainerman schrieb:

> Let's assume two devices are connected by p2p link via unnumbered
> interfaces:
>
> |=====| |=====|
> | | Ser0 | |
> | A 0-------------------0 B 0-----Network 10.0.3.0/24
> | | Ser0 | |
> |=====| |=====|
>
> Both interfaces are unnumbered and each one shares the IP address with
> the device's loopback.
>
> A's loppback is 10.0.1.1/24
> B's loopback is 10.0.2.1/24
>
> How does routing table od router A look like ?
>
> S 10.0.3.0 [1/1] via 10.0.2.1, Serial0 ?
>
> Would I see network 10.0.2.0/24 as a connected ?
>
> C 10.0.2.0/24 is directly connected, Serial0 ?
>
> Thanks, Evgeny.


 
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