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Hello All,

Here is a small C program,

main()
{
int a= 100;
float b =99.99;
TEST(a,%d);
TEST(b,%f);
}

Now I want to write a macro for TEST such that it outputs something like this

main()
{
int a=100;
float b =99.99;
printf(" The value of a = %d \n",a);
printf(" The value of b = %f \n",b);
}

I tried to write macro like this, but its not working

#define TEST(a,b) printf(" The value of a = b \n",a)

Can somebody help me in this?

Thanks
-Vittal

On Thu, 3 Jul 2003, Vittal wrote:
>
> TEST(a,%d);
> TEST(b,%f);
>
> Now I want to write a macro for TEST such that it outputs something like this
>
> printf(" The value of a = %d \n",a);
> printf(" The value of b = %f \n",b);
>
> I tried to write macro like this, but its not working
>
> #define TEST(a,b) printf(" The value of a = b \n",a)

Try

#define TEST(a,b) printf(" The value of " #a " = " #b " \n", a)

(The syntax #foo is a special preprocessing thingamabob that says
"take the value of foo and stick it in a string literal." Putting
two string literals next to each other - "foo" "bar" - concatenates
them - producing the equivalent of "foobar". [This *only* works with
compile-time literals!] So the above stringizes 'a' and 'b' and
sticks them in the string.)

Untested code, may not work if a or b are macros themselves. I.e.,

TEST(INT_MAX, %d);

may do incorrect things. Someone else will post that FAQ.

-Arthur

In article < >, Vittal wrote:
> Hello All,
> #define TEST(a,b) printf(" The value of a = b \n",a)

#define TEST(a,b) printf("The value of " #a " = " #b "\n", a)

Interresting question in fact.

Marc Boyer
--
Lying for having sex or lying for making war? Trust US presidents

"Vittal" <> wrote in message
news: om...
> Hello All,
>
> Here is a small C program,
>
> main()
> {
> int a= 100;
> float b =99.99;
> TEST(a,%d);
> TEST(b,%f);
> }
>
> Now I want to write a macro for TEST such that it outputs something like
this
>
> main()
> {
> int a=100;
> float b =99.99;
> printf(" The value of a = %d \n",a);
> printf(" The value of b = %f \n",b);
> }
>
> I tried to write macro like this, but its not working
>
> #define TEST(a,b) printf(" The value of a = b \n",a)
>
> Can somebody help me in this?
>
> Thanks
> -Vittal

Hi Vittal,

You can use the define:
#define TEST(fmt,val) ((void)printf("The value of %s = "fmt"\n",#val,val))
The format(fmt) is just a string and is concatenated with the rest of the
strings.
#val is also a string (so "a" or "b" in your example)
val is the value.

Marco

#include <stdio.h>

#define TEST(fmt,val) ((void)printf("The value of %s = "fmt"\n",#val,val))

int main()
{
int a=100;
float b=99.99F;

TEST("%d",a);
TEST("%f",b);
return 0;
}

In < > (Vittal) writes:

>main()
>{
>int a= 100;
>float b =99.99;
>TEST(a,%d);
>TEST(b,%f);
>}
>
>Now I want to write a macro for TEST such that it outputs something like this
>
>main()
>{
>int a=100;
>float b =99.99;
>printf(" The value of a = %d \n",a);
>printf(" The value of b = %f \n",b);
>}
>
>I tried to write macro like this, but its not working
>
>#define TEST(a,b) printf(" The value of a = b \n",a)

Obviously, since the preprocessor doesn't touch the contents of string
literals.

>Can somebody help me in this?

Use the # operator and take advantage of the adjacent string splicing
feature of C:

#define TEST(a,b) printf(" The value of " #a " = " #b " \n", a)

Not very easy to read, but it gets the job done.

Dan
--
Dan Pop
DESY Zeuthen, RZ group
Email: