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Hi! I'm struggling with doing this in an elegant way -- I'll get my
XSLT books out of storage this weekend, but for now I could use some
help.
<bedknob>
<broomstick>
<bippity>boppity</bippity>
</broomstick>
<broomstick>
<bippity>boppity</bippity>
<bippity>boo</bippity>
</broomstick>
</bedknob>
I'd like to get the complete list of bippities, then compare the
bippities of each broomstick to them, and make a mark for each present
member of the complete set of bippities in a particular broomstick,
like
<table>
<thead>
<tr>
<th>boppity
</th>
<th>boo
</th>
</tr>
</thead>
<tbody>
<tr>
<td>X
</td>
<td>
</td>
</tr>
<tr>
<td>X
</td>
<td>X
</td>
</tr>
</tbody>
</table>

OK. So, I use a Muenchian sort to get the unique list of bippities for
the thead element, but then to do the rows in the body, I have to go
through it again, and check each member against the set of present
values. I'm thinking of something like taking the intersection and
looking for count() = 2, but I'm having trouble making it happen.

Can you help me?

Ion

Hi,

On Fri, 02 Jun 2006 21:54:32 +0200, ion <> wrote:

> Hi! I'm struggling with doing this in an elegant wayI'd like to get the
> complete list of bippities, then compare the
> bippities of each broomstick to them, and make a mark for each present
> member of the complete set of bippities in a particular broomstick,
> like


I have no idea if this will conform to your idea of elegance (it uses
plain dumb for-each loops), but this solution seems to work:

<xsl:stylesheet version="1.0"
xmlnssl="http://www.w3.org/1999/XSL/Transform">
<xslutput method="xml" indent="yes"/>

<xsl:key name="b" match="bippity" use="."/>
<xsl:variable name="bip"
select="//*[generate-id()=generate-id(key('b',.)[1])]"/>

<xsl:template match="bedknob">
<table>
<thead>
<tr>
<xsl:for-each select="$bip">
<th><xsl:value-of select="."/></th>
</xsl:for-each>
</tr>
</thead>
<tbody>
<xsl:apply-templates select="broomstick"/>
</tbody>
</table>
</xsl:template>

<xsl:template match="broomstick">
<xsl:variable name="this" select="bippity"/>
<tr>
<xsl:for-each select="$bip">
<td>
<xsl:if test=".=$this">X</xsl:if>
</td>
</xsl:for-each>
</tr>
</xsl:template>

</xsl:stylesheet>


regards,
--
Joris Gillis (http://users.telenet.be/root-jg/me.html)
Veni, vidi, wiki (http://www.wikipedia.org)

Thanks, Joris, that works great.
Ion

Joris Gillis wrote:
> Hi,
>
> On Fri, 02 Jun 2006 21:54:32 +0200, ion <> wrote:
>
> > Hi! I'm struggling with doing this in an elegant wayI'd like to get the
> > complete list of bippities, then compare the
> > bippities of each broomstick to them, and make a mark for each present
> > member of the complete set of bippities in a particular broomstick,
> > like
>
>
> I have no idea if this will conform to your idea of elegance (it uses
> plain dumb for-each loops), but this solution seems to work:
>
> <xsl:stylesheet version="1.0"
> xmlnssl="http://www.w3.org/1999/XSL/Transform">
> <xslutput method="xml" indent="yes"/>
>
> <xsl:key name="b" match="bippity" use="."/>
> <xsl:variable name="bip"
> select="//*[generate-id()=generate-id(key('b',.)[1])]"/>
>
> <xsl:template match="bedknob">
> <table>
> <thead>
> <tr>
> <xsl:for-each select="$bip">
> <th><xsl:value-of select="."/></th>
> </xsl:for-each>
> </tr>
> </thead>
> <tbody>
> <xsl:apply-templates select="broomstick"/>
> </tbody>
> </table>
> </xsl:template>
>
> <xsl:template match="broomstick">
> <xsl:variable name="this" select="bippity"/>
> <tr>
> <xsl:for-each select="$bip">
> <td>
> <xsl:if test=".=$this">X</xsl:if>
> </td>
> </xsl:for-each>
> </tr>
> </xsl:template>
>
> </xsl:stylesheet>
>
>
> regards,
> --
> Joris Gillis (http://users.telenet.be/root-jg/me.html)
> Veni, vidi, wiki (http://www.wikipedia.org)