On 14 Jun 2005 18:49:13 -0700, "Chaz" <> wrote in
comp.lang.c++:
> Hello, I hope someone can help me out. I am going to be taking the
> third step in a programming class soon(I took the previous two a while
> ago at a different school) and in an effort to get back up to speed, I
> bought the Dietel book How To Program 5th ed. I am going through some
> examples trying to work them out, and have been doing pretty good, but
> came across one exercise that has me stumped. It's a card shuffling
> program that deals 5 cards, and stores the face value and suit in
> arrays respectively. I have pasted the code which I hope shows that.
>
> // to deal only 5 cards for a poker hand
> for ( int card = 1; card <= 5; card++ )
> {
> // loop through rows of deck
> for ( int row = 0; row <= 3; row++ )
> {
> // loop through columns of deck for current row
> for ( int column = 0; column <= 12; column++ )
> {
> // if slot contains current card, display card
> if ( deck[ row ][ column ] == card )
> {
> cout << setw( 5 ) << right << face[ column ]
> << " of " << setw( 8 ) << left << suit[ row ]
> << ( card % 2 == 0 ? '\n' : '\t' );
> } // end if
> } // end innermost for
> } // end inner for
> } // end outer for
>
> What this example asks to do is to modify the program so that it can
> determine if the hand has a pair. (and three of a kind and so on)
> Considering the "cards" are stored in arrays, how would you compare all
> 5 face values for example and be able to tell their are two of a kind?
>
> Thanks for taking the time to look at this and any help you can
> provide.
>
> Chaz
I'll give you a suggestion, not the code.
Create an array of 13 ints, one for each face value, and initialize
all the elements of this array to 0. Decide on a mapping between the
13 different card faces, if the program does not provide one already.
Now look at each of the 5 cards in the hand. For each card, increment
the element of the array that corresponds to its face value.
Final step, loop through the 13 elements of the array. If any element
has the value 2, you have a pair of the corresponding card face. If
any element has 3, you have three of a kind, a 4 means four of a kind,
and a 5 means you are playing with a crooked deck.
--
Jack Klein
Home:
http://JK-Technology.Com
FAQs for
comp.lang.c
http://www.eskimo.com/~scs/C-faq/top.html
comp.lang.c++
http://www.parashift.com/c++-faq-lite/
alt.comp.lang.learn.c-c++
http://www.contrib.andrew.cmu.edu/~a...FAQ-acllc.html