«

i need help pretty bad for this

from the command line

>csend string1 4233 "string2"

how can i copy string1, or string2 to a char* or a string.


for argument 4 (string2)

char temp[256];
strcpy(temp, argv[4]);

this doesn't work
------------
int i;
char temp[256];
for(i=1; argv[4][i] != '"'; ++i)
{
temp[i] = argv[4][i];
}
temp[i] = '\0'

neither does this - gives a seg fault on this line
for(i=1; argv[4][i] != '"'; ++i)

how do i do it. and why don't these techniques work

On Sat, 08 May 2004 15:42:03 GMT in comp.lang.c++, "Ashe Corven"
<cfitzgib@@bigpond.net.au> wrote,
>from the command line
>
>>csend string1 4233 "string2"
>
>how can i copy string1, or string2 to a char* or a string.
>
>
>for argument 4 (string2)
>
>char temp[256];
>strcpy(temp, argv[4]);

Main reason being that string2 is argv[3] ?


int main(int argc, char *argv[])
{
cout << "argc = " << argc << '\n';
for(int argx = 0; argx < argc; argx++) {
cout << "argv[" << argx << "] = \"" << argv[argx] << "\"\n");
}
return 0;
}

oh ****
haha
"David Harmon" <> wrote in message
news:...
> On Sat, 08 May 2004 15:42:03 GMT in comp.lang.c++, "Ashe Corven"
> <cfitzgib@@bigpond.net.au> wrote,
> >from the command line
> >
> >>csend string1 4233 "string2"
> >
> >how can i copy string1, or string2 to a char* or a string.
> >
> >
> >for argument 4 (string2)
> >
> >char temp[256];
> >strcpy(temp, argv[4]);
>
> Main reason being that string2 is argv[3] ?
>
>
> int main(int argc, char *argv[])
> {
> cout << "argc = " << argc << '\n';
> for(int argx = 0; argx < argc; argx++) {
> cout << "argv[" << argx << "] = \"" << argv[argx] << "\"\n");
> }
> return 0;
> }
>

In message <fd7nc.27672$>, Ashe Corven
<cfitzgib@?.net.au.invalid> writes
>i need help pretty bad for this
>
>from the command line
>
>>csend string1 4233 "string2"
>
>how can i copy string1, or string2 to a char* or a string.
>
>
>for argument 4 (string2)
>
>char temp[256];
>strcpy(temp, argv[4]);
>
>this doesn't work
>------------
>int i;
>char temp[256];
>for(i=1; argv[4][i] != '"'; ++i)
>{
> temp[i] = argv[4][i];
>}
>temp[i] = '\0'
>
>neither does this - gives a seg fault on this line
>for(i=1; argv[4][i] != '"'; ++i)
>
>how do i do it. and why don't these techniques work
>
>

The four command line arguments are pointed to by:
argv[0] // pointer to the name of the program
argv[1] // pointer to string1
argv[2] // pointer to 4233
argv[3] // pointer to string2

Remember that in C (and C++) we count from 0.


--
Francis Glassborow ACCU
Author of 'You Can Do It!' see http://www.spellen.org/youcandoit
For project ideas and contributions: http://www.spellen.org/youcandoit/projects