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I have 4 overloaded functions 'deallocate':

template <typename T> void deallocate(T* mem);
template <typename T> void deallocate(T** mem);
template <typename T> void deallocate(T*** mem);
template <typename T> void deallocate(T**** mem);

When i try to compile code like:

double ***image= allocate<double>(bands, rows, columns);
deallocate(image);

I get the following errors:

error C2667: 'deallocate' : none of 3 overload have a best conversion
error C2668: 'deallocate' : ambiguous call to overloaded function

When I write deallocate<double>(image) or deallocate<>(image), it compiles
without errors.
Why is this necessary? Or is it this only a problem with MSVC6?

Jef Driesen wrote:

> I have 4 overloaded functions 'deallocate':
>
> template <typename T> void deallocate(T* mem);
> template <typename T> void deallocate(T** mem);
> template <typename T> void deallocate(T*** mem);
> template <typename T> void deallocate(T**** mem);
>
> When i try to compile code like:
>
> double ***image= allocate<double>(bands, rows, columns);
> deallocate(image);
>
> I get the following errors:
>
> error C2667: 'deallocate' : none of 3 overload have a best conversion
> error C2668: 'deallocate' : ambiguous call to overloaded function
>
> When I write deallocate<double>(image) or deallocate<>(image), it compiles
> without errors.
> Why is this necessary? Or is it this only a problem with MSVC6?
>
It is a problem with MSVC 6.

Michael Mellor