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[ntg]

I think this should do the trick in an efficient way...
its even using the faster ++it....

int high_cutoff = 10;
vector<CUnit>::reverse_iterator it;
for (it = good_list.rbegin(); it != good_list.rend(); ) {
if (it->GetCutoff() >= high_cutoff) {
it = good_list.erase(it.base()-1);
}
else {
++it;
}
}

any thoughts?