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Output of followin program at Turbo C++ 3.0 is 7 ( Not 2 or 3).

Please explain why ?

////////////////////////////////////////////////
#include<stdio.h>
#include<string.h>

void main()
{
char ch[]={'a','b'};

int len;
len=strlen(ch);

printf("%d\n",len);
}
////////////////////////////////////////////////

"Sanjeev" <> wrote in message
news: om...
> Output of followin program at Turbo C++ 3.0 is 7 ( Not 2 or 3).
>
> Please explain why ?
>
> ////////////////////////////////////////////////
> #include<stdio.h>
> #include<string.h>
>
> void main()
> {
> char ch[]={'a','b'};
>
> int len;
> len=strlen(ch);
>
> printf("%d\n",len);
> }
> ////////////////////////////////////////////////

This is actually undefined, since ch is an array of chars but is not null
terminated, if you had
char ch[] = "ab";
or
char ch[] = {'a','b','\0'};
then this would be fine and you would get your expected result
Allan

"Allan Bruce" <> wrote...
>
> "Sanjeev" <> wrote in message
> news: om...
> > Output of followin program at Turbo C++ 3.0 is 7 ( Not 2 or 3).
> >
> > Please explain why ?
> >
> > ////////////////////////////////////////////////
> > #include<stdio.h>
> > #include<string.h>
> >
> > void main()
> > {
> > char ch[]={'a','b'};
> >
> > int len;
> > len=strlen(ch);
> >
> > printf("%d\n",len);
> > }
> > ////////////////////////////////////////////////
>
> This is actually undefined, since ch is an array of chars but is not null
> terminated, if you had
> char ch[] = "ab";
> or
> char ch[] = {'a','b','\0'};
> then this would be fine and you would get your expected result
> Allan

Absolutely! Another reason why it's undefined is because the 'main'
function does not return 'int' (as it's supposed to).

Victor

Sanjeev wrote:

> Output of followin program at Turbo C++ 3.0 is 7 ( Not 2 or 3).

You have posted this guestion to C++ and C groups. Please deside what
language you are learning. Is it C or is it C++? ( They are not the same
language )