IBUFG and BUFG +xilinx

Hello Guys,
I had a doubt about the IBUFG and BUFG in xilinx.
1.I have connected clock from oscillator to CLKG IO of the Xilinx. In
this case is it required to instantiate the IBUFG inside my code
also?.
2. The DCM output is already BUFG i think and so is it required to
BUFG again in my code?

Thanks and regards
Williams

williams

williams wrote:
> Hello Guys,
> I had a doubt about the IBUFG and BUFG in xilinx.
> 1.I have connected clock from oscillator to CLKG IO of the Xilinx. In
> this case is it required to instantiate the IBUFG inside my code
> also?.

Howdy Williams,

I believe the tools will usually do it for you - the exception that
comes to mind is differential clocks.

> 2. The DCM output is already BUFG i think and so is it required to
> BUFG again in my code?

BUFG is another name for a global buffer. Although most of the time
you'd want it on a global buffer, the output of a DCM is not "already
BUFG", nor would you always want it to be. Even if it does automaticly
insert a BUFG in some situations, I rarely trust that it will every
time.

Have fun,

Marc

Marc Randolph

Williams,

By default, an IBUFG & BUFG are instantiated, but if you specify something
like:

wire dcmclkout;
// synthesis attribute clock_signal of dcmclkout is true
// synthesis attribute clock_buffer of dcmclkout is none

the synthesis tool will not issue a clock buffer placement.

i usually instantiate IBUFG & BUFG, for safety.
hope this helps.

Vladislav

"williams" <> wrote in message
news: om...
> Hello Guys,
> I had a doubt about the IBUFG and BUFG in xilinx.
> 1.I have connected clock from oscillator to CLKG IO of the Xilinx. In
> this case is it required to instantiate the IBUFG inside my code
> also?.
> 2. The DCM output is already BUFG i think and so is it required to
> BUFG again in my code?
>
> Thanks and regards
> Williams

Vladislav Muravin