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#2 |
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For active high:
LedOut <= '1' ; For a simple on/off with a switch: LedOut <= SwitchIn ; Of course you probably should debounce the switch input and register the LedOut output. For debounce, do a search of the newsgroup. Assume that your switch is bouncing if it has not been stable for anywhere from 5 ms to 15 ms. If you bought your board, there may be a test code that your vendor provides that does this. Cheers, Jim network lines wrote: > Hello...i am new to VHDL, and learning how to > program using a Cypress CPLD. > Anybody got some simple code to turn on and turn off > an LED??? > please email sample code to > > TIA -- ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ ~~~~~~~~~~~ Jim Lewis Director of Training private.php?do=newpm&u= SynthWorks Design Inc. http://www.SynthWorks.com 1-503-590-4787 Expert VHDL Training for Hardware Design and Verification ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ ~~~~~~~~~~~ Jim Lewis |
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#3 |
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If the switch just results in turning of and off a LED used as an
indicator, there is no need to debounce it. Debounce becomes important if the fact that the switch turns on and off many times within a millisecond or so after it is actuated disturbs the operation of your circuit. Something like a counter that counts how many times the switch is operated would need debounce. Simply turning on and off the led to follow the switch movement does not. Likewise, dipswitches used to set modes often do not require debouncing. They can either be accepted as is, or in many cases are read at one particular instant during some initialization, so debounce is not needed. Only if the operation of the switch causes an immediate action is the debounce needed. Jim Lewis wrote: > For active high: > LedOut <= '1' ; > > For a simple on/off with a switch: > LedOut <= SwitchIn ; > > Of course you probably should debounce the switch input > and register the LedOut output. For debounce, > do a search of the newsgroup. Assume that your > switch is bouncing if it has not been stable for > anywhere from 5 ms to 15 ms. > > If you bought your board, there may be a test > code that your vendor provides that does this. > > Cheers, > Jim > > network lines wrote: > > Hello...i am new to VHDL, and learning how to > > program using a Cypress CPLD. > > Anybody got some simple code to turn on and turn off > > an LED??? > > please email sample code to > > > > TIA > > -- > ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ ~~~~~~~~~~~ > Jim Lewis > Director of Training private.php?do=newpm&u= > SynthWorks Design Inc. http://www.SynthWorks.com > 1-503-590-4787 > > Expert VHDL Training for Hardware Design and Verification > ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ ~~~~~~~~~~~ -- --Ray Andraka, P.E. President, the Andraka Consulting Group, Inc. 401/884-7930 Fax 401/884-7950 http://www.andraka.com "They that give up essential liberty to obtain a little temporary safety deserve neither liberty nor safety." -Benjamin Franklin, 1759 Ray Andraka |
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#4 |
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Jim Lewis wrote:
> For active high: > LedOut <= '1' ; > > For a simple on/off with a switch: > LedOut <= SwitchIn ; Or save some fpga resources like this: VCC____/.-----[>|-----/\/\/--- GND http://home.comcast.net/~mike_treseler/rimshot.wav -- Mike Treseler Mike Treseler |
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#5 |
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My conservative suggestion to debounce is concern over
noise causing the lifetime of the LED to be shorter. Perhaps this is not a concern? I know in my house some light bulbs seem to burn out faster than others and I have always wondered if it was due to excessive noise from the switches (look nice, but knowing the builder they are probably low cost). Cheers, Jim > If the switch just results in turning of and off a LED used as an > indicator, there is no need to debounce it. Debounce becomes > important if the fact that the switch turns on and off many times > within a millisecond or so after it is actuated disturbs the > operation of your circuit. Something like a counter that counts > how many times the switch is operated would need debounce. > Simply turning on and off the led to follow the switch movement > does not. > > Likewise, dipswitches used to set modes often do not require > debouncing. They can either be accepted as is, or in many cases > are read at one particular instant during some initialization, so > debounce is not needed. Only if the operation of the switch > causes an immediate action is the debounce needed. > > Jim Lewis wrote: > > >>For active high: >> LedOut <= '1' ; >> >>For a simple on/off with a switch: >> LedOut <= SwitchIn ; >> >>Of course you probably should debounce the switch input >>and register the LedOut output. For debounce, >>do a search of the newsgroup. Assume that your >>switch is bouncing if it has not been stable for >>anywhere from 5 ms to 15 ms. >> >>If you bought your board, there may be a test >>code that your vendor provides that does this. >> >>Cheers, >>Jim >> >>network lines wrote: >> >>>Hello...i am new to VHDL, and learning how to >>>program using a Cypress CPLD. >>>Anybody got some simple code to turn on and turn off >>>an LED??? >>>please email sample code to >>> >>>TIA >> >>-- >>~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ ~~~~~~~~~~~~~ >>Jim Lewis >>Director of Training private.php?do=newpm&u= >>SynthWorks Design Inc. http://www.SynthWorks.com >>1-503-590-4787 >> >>Expert VHDL Training for Hardware Design and Verification >>~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ ~~~~~~~~~~~~~ > > > -- > --Ray Andraka, P.E. > President, the Andraka Consulting Group, Inc. > 401/884-7930 Fax 401/884-7950 > http://www.andraka.com > > "They that give up essential liberty to obtain a little > temporary safety deserve neither liberty nor safety." > -Benjamin Franklin, > 1759 > > -- ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ ~~~~~~~~~~~ Jim Lewis Director of Training private.php?do=newpm&u= SynthWorks Design Inc. http://www.SynthWorks.com 1-503-590-4787 Expert VHDL Training for Hardware Design and Verification ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ ~~~~~~~~~~~ Jim Lewis |
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#6 |
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Hi Jim,
I don't think it matters mate. I know almost all the 7 segment LED displays I've seen, e.g. on frequency counters, are multiplexed. Thus they're flashing on and off 'faster than the human eye'! You can see this if you snort like a pig while watching them! Honest! It's something to do with the snort vibrating your head. Cheers, Syms. "Jim Lewis" <> wrote in message news:... > My conservative suggestion to debounce is concern over > noise causing the lifetime of the LED to be shorter. > Perhaps this is not a concern? > > I know in my house some light bulbs seem to burn out > faster than others and I have always wondered if it > was due to excessive noise from the switches (look > nice, but knowing the builder they are probably > low cost). > > Cheers, > Jim Symon |
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#7 |
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"Jim Lewis" <> escribió en el mensaje news:... > My conservative suggestion to debounce is concern over > noise causing the lifetime of the LED to be shorter. > Perhaps this is not a concern? > > I know in my house some light bulbs seem to burn out > faster than others and I have always wondered if it > was due to excessive noise from the switches (look > nice, but knowing the builder they are probably > low cost). > > Cheers, > Jim > actually i think it's because of the light bulb being turned on when the electric current sinus feeding it is not zero or near zero volts, which causes stress on the bulb filament (the thin tunsgten wire that lights) LEDs being solid state devices (and using a different light emitting pheanomenon than bulbs), i dont think they have this problem > > > > If the switch just results in turning of and off a LED used as an > > indicator, there is no need to debounce it. Debounce becomes > > important if the fact that the switch turns on and off many times > > within a millisecond or so after it is actuated disturbs the > > operation of your circuit. Something like a counter that counts > > how many times the switch is operated would need debounce. > > Simply turning on and off the led to follow the switch movement > > does not. > > > > Likewise, dipswitches used to set modes often do not require > > debouncing. They can either be accepted as is, or in many cases > > are read at one particular instant during some initialization, so > > debounce is not needed. Only if the operation of the switch > > causes an immediate action is the debounce needed. > > > > Jim Lewis wrote: > > > > > >>For active high: > >> LedOut <= '1' ; > >> > >>For a simple on/off with a switch: > >> LedOut <= SwitchIn ; > >> > >>Of course you probably should debounce the switch input > >>and register the LedOut output. For debounce, > >>do a search of the newsgroup. Assume that your > >>switch is bouncing if it has not been stable for > >>anywhere from 5 ms to 15 ms. > >> > >>If you bought your board, there may be a test > >>code that your vendor provides that does this. > >> > >>Cheers, > >>Jim > >> > >>network lines wrote: > >> > >>>Hello...i am new to VHDL, and learning how to > >>>program using a Cypress CPLD. > >>>Anybody got some simple code to turn on and turn off > >>>an LED??? > >>>please email sample code to > >>> > >>>TIA > >> > >>-- > >>~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ ~~~~~~~~~~~~~ > >>Jim Lewis > >>Director of Training private.php?do=newpm&u= > >>SynthWorks Design Inc. http://www.SynthWorks.com > >>1-503-590-4787 > >> > >>Expert VHDL Training for Hardware Design and Verification > >>~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ ~~~~~~~~~~~~~ > > > > > > -- > > --Ray Andraka, P.E. > > President, the Andraka Consulting Group, Inc. > > 401/884-7930 Fax 401/884-7950 > > http://www.andraka.com > > > > "They that give up essential liberty to obtain a little > > temporary safety deserve neither liberty nor safety." > > -Benjamin Franklin, > > 1759 > > > > > > > -- > ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ ~~~~~~~~~~~ > Jim Lewis > Director of Training private.php?do=newpm&u= > SynthWorks Design Inc. http://www.SynthWorks.com > 1-503-590-4787 > > Expert VHDL Training for Hardware Design and Verification > ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ ~~~~~~~~~~~ paris |
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#8 |
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LEDs don't burn out due to turn on/off. In fact, a common way of
varying the brightness in LED displays is to pulse width modulate the driving voltage. Light bulbs burn out faster on turn on/off cycles because the wire resistance is lower when it is cold, and when turned on it has a surge of current much higher than the on current. LEDs are a different mechanism for producing the light. I doubt that noise on the switch is going to alter incadesant lamp life much, the on-off cycles are way to fast to get the shock heating that happens when you turn them on. Jim Lewis wrote: > My conservative suggestion to debounce is concern over > noise causing the lifetime of the LED to be shorter. > Perhaps this is not a concern? > > I know in my house some light bulbs seem to burn out > faster than others and I have always wondered if it > was due to excessive noise from the switches (look > nice, but knowing the builder they are probably > low cost). > -- > ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ ~~~~~~~~~~~ > Jim Lewis > Director of Training private.php?do=newpm&u= > SynthWorks Design Inc. http://www.SynthWorks.com > 1-503-590-4787 > > Expert VHDL Training for Hardware Design and Verification > ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ ~~~~~~~~~~~ -- --Ray Andraka, P.E. President, the Andraka Consulting Group, Inc. 401/884-7930 Fax 401/884-7950 http://www.andraka.com "They that give up essential liberty to obtain a little temporary safety deserve neither liberty nor safety." -Benjamin Franklin, 1759 Ray Andraka |
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#9 |
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Indeed, but it's not the excess turn on current per se that blows the bulb,
it's the thermal stress on the filament which expands as it heats up. The lower filament resistance at cold means it heats up faster than it would if the resistance stayed constant. There are stories of light bulbs in fire stations that are permanently on that last for many decades. check out http://www.firehouse.com/news/2001/6/11_bulb.html . 100 years and still going. cheers, Syms. "Ray Andraka" <> wrote in message news:... > Light bulbs burn out faster on turn on/off cycles because the wire > resistance is lower when it is cold, and when turned on it has a surge > of current much higher than the on current. Symon |
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