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VHDL - Propagation delay trought a control signal "SEL" of a MUX |
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#1 |
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Hi
I am using synplify to synthesis my vhdl design code. the code is an Add_Compare_Select (ACS) opearation for radix-2 butterfly used in the most of error correcting decoders. Lets say : the inputs are A,B,C & D vectors the operation is : (A+B)>(C+D) the output is the result of the smallest of (A+B) & (C+D)this is done by combinatory logic and folowed by a D flip-flop. Now if I synthesis this design, I obtaine fmax=150 Mhz. Now if i add a Mux in the B and D paths so now i have a 2Mux feeding the operations (A+B)>(C+D) whit B and D values accordantly. The control (sel) of a MUX is kind of fix value (a config value that we fix in the begining of simulation and we dont change it) so that way a MUX is playing a role of a switch. The probleme is when i synthetis this design it give me 98 Mhz. The question is : is there any way to tel to the synthesis tool that a control signal (sel) for the MUX's is statistic, calculate only the propagation delay through the MUX (from the in tel the out)whitout taking in acount propagation delay of sel. And a such way that the synthesis tool wil not ignore a mux and will not relpace it by a direct wire. A,B,C & D are 8 bits , MUX is 16:1 Oleg |
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#2 |
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Posts: n/a
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Hi Oleg
Don't rely on the synthesis fmax estimated value, use actual fmax given by the PAR tool. If you're using XST, you can use the UCF file to say NET "sel" TIG; which basically tells the par tool to ignore all paths starting at sel A completely different matter is if the MUX will be present in your design. Only if there exists the possibility to change the sel value at run-time (using an external input pad, for example) the MUX is required. It will be trimmed otherwise. Regards Francisco "Oleg" <> escribió en el mensaje news: om... > Hi > > I am using synplify to synthesis my vhdl design code. the code is an > Add_Compare_Select (ACS) opearation for radix-2 butterfly used in the > most of error correcting decoders. Lets say : the inputs are A,B,C & D > vectors the operation is : (A+B)>(C+D) the output is the result of the > smallest of (A+B) & (C+D)this is done by combinatory logic and folowed > by a D flip-flop. > > Now if I synthesis this design, I obtaine fmax=150 Mhz. > > Now if i add a Mux in the B and D paths so now i have a 2Mux feeding > the operations (A+B)>(C+D) whit B and D values accordantly. The > control (sel) of a MUX is kind of fix value (a config value that we > fix in the begining of simulation and we dont change it) so that way a > MUX is playing a role of a switch. > > The probleme is when i synthetis this design it give me 98 Mhz. > > The question is : is there any way to tel to the synthesis tool that a > control signal (sel) for the MUX's is statistic, calculate only the > propagation delay through the MUX (from the in tel the out)whitout > taking in acount propagation delay of sel. And a such way that the > synthesis tool wil not ignore a mux and will not relpace it by a > direct wire. > > A,B,C & D are 8 bits , MUX is 16:1 Francisco Rodriguez |
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