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Hello,
I am new to xslt and try to have an argument that for each iteration
of the "FOR-EACH" will grow in one:

<xsl:for-each select="//AssetCode">
<node id="_1">
<xsl:attribute name="text">
<xsl:value-of select="."/>
</xsl:attribute>
</node>


I want id to be in the next iteration _2 and _3 in the next one
etc....

any ideas of how to do it?

(Eyal) wrote in message news:<. com>...
> Hello,
> I am new to xslt and try to have an argument that for each iteration
> of the "FOR-EACH" will grow in one:
>
> <xsl:for-each select="//AssetCode">
> <node id="_1">
> <xsl:attribute name="text">
> <xsl:value-of select="."/>
> </xsl:attribute>
> </node>
>
>
> I want id to be in the next iteration _2 and _3 in the next one
> etc....
>
> any ideas of how to do it?

I learned a lot from this article.

http://www.xml.com/pub/a/2001/08/01/gettingloopy.html

(Eyal) writes:

> Hello,
> I am new to xslt and try to have an argument that for each iteration
> of the "FOR-EACH" will grow in one:
>
> <xsl:for-each select="//AssetCode">
> <node id="_1">
> <xsl:attribute name="text">
> <xsl:value-of select="."/>
> </xsl:attribute>
> </node>
>
>
> I want id to be in the next iteration _2 and _3 in the next one
> etc....
>
> any ideas of how to do it?

Use the XPath position() function.

These data

<test>
<AssetCode>abc</AssetCode>
<AssetCode>def</AssetCode>
<AssetCode>ghi</AssetCode>
<AssetCode>jkl</AssetCode>
</test>

with a very slight modification to your stylesheet:

<xsl:stylesheet
version="1.0"
xmlnssl="http://www.w3.org/1999/XSL/Transform"
>

<xsl:template match="/">
<xsl:for-each select="//AssetCode">
<node id="_{position()}">
<xsl:attribute name="text">
<xsl:value-of select="."/>
</xsl:attribute>
</node>
</xsl:for-each>
</xsl:template>

</xsl:stylesheet>


Gives this output

<?xml version="1.0"?>
<node id="_1" text="abc"/><node id="_2" text="def"/>
<node id="_3" text="ghi"/><node id="_4" text="jkl"/>


Ben

--
Ben Edgington
Mail to the address above is discarded.
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www.edginet.org

Thanks Ben, It works great.

Ben Edgington <> wrote in message news:<>...
> (Eyal) writes:
>
> > Hello,
> > I am new to xslt and try to have an argument that for each iteration
> > of the "FOR-EACH" will grow in one:
> >
> > <xsl:for-each select="//AssetCode">
> > <node id="_1">
> > <xsl:attribute name="text">
> > <xsl:value-of select="."/>
> > </xsl:attribute>
> > </node>
> >
> >
> > I want id to be in the next iteration _2 and _3 in the next one
> > etc....
> >
> > any ideas of how to do it?
>
> Use the XPath position() function.
>
> These data
>
> <test>
> <AssetCode>abc</AssetCode>
> <AssetCode>def</AssetCode>
> <AssetCode>ghi</AssetCode>
> <AssetCode>jkl</AssetCode>
> </test>
>
> with a very slight modification to your stylesheet:
>
> <xsl:stylesheet
> version="1.0"
> xmlnssl="http://www.w3.org/1999/XSL/Transform"
> >
>
> <xsl:template match="/">
> <xsl:for-each select="//AssetCode">
> <node id="_{position()}">
> <xsl:attribute name="text">
> <xsl:value-of select="."/>
> </xsl:attribute>
> </node>
> </xsl:for-each>
> </xsl:template>
>
> </xsl:stylesheet>
>
>
> Gives this output
>
> <?xml version="1.0"?>
> <node id="_1" text="abc"/><node id="_2" text="def"/>
> <node id="_3" text="ghi"/><node id="_4" text="jkl"/>
>
>
> Ben