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Hi all,

I'm starting to learn XSLT - and have what I think is a very basic
question:

I have a stylesheet like this:

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlnssl="http://www.w3.org/1999/XSL/Transform"
version="1.0">
<xslaram name="objectname"/>

<xsl:template match="/Root">
<xsl:apply-templates select="./$objectname"/>
</xsl:template>

<xsl:template match="$objectname">
<Result>
<xsl:value-of select="."/>
</Result>
</xsl:template>

</xsl:stylesheet>

and XML like this:

<?xml version="1.0" ?>
<Root>
<Value1>1</Value1>
<Value2>2</Value2>
<Value3>3</Value3>
</Root>



Now, I'd like to pass a name of a child element of Root (like Value1
or Value2) from a Java class into this stylesheet as param
'objectname'.

I can pass the parameter fine (I have tested this), but I understand
that this won't work because the XSLT interpretor cannot resolve the
value of $objectname as part of an XPath expression representing a
nodeset.

What I'd like to know is if there is some way to accomplish the same
thing ? I apologize if this question has been asked a million times by
a million newbies in the past, but I haven't found a way to do it yet
- I've even considered resorting to something 'strange' like running
my XSLT template through another XSLT template that resolves all the
'parameterized XPath expressions' into their explicit forms - but that
feels 'terribly inelegant'.

Thanks in advance - please reply directly as above.
Colin

On 22/01/2004, around 15:14, Colin Toal wrote:

CT> What I'd like to know is if there is some way to accomplish the same
CT> thing ?

Try

<xsl:template match="/Root">
<xsl:apply-templates select="./*[name() = $objectname]"/>
</xsl:template>

--
Stuart
The darkest hour is just before dawn. So if you're going to steal your
neighbour's milk, that's the time to do it.

Colin Toal wrote:


> I have a stylesheet like this:
>
> <?xml version="1.0" encoding="UTF-8"?>
> <xsl:stylesheet xmlnssl="http://www.w3.org/1999/XSL/Transform"
> version="1.0">
> <xslaram name="objectname"/>
>
> <xsl:template match="/Root">
> <xsl:apply-templates select="./$objectname"/>
> </xsl:template>
>
> <xsl:template match="$objectname">
> <Result>
> <xsl:value-of select="."/>
> </Result>
> </xsl:template>
>
> </xsl:stylesheet>
>
> and XML like this:
>
> <?xml version="1.0" ?>
> <Root>
> <Value1>1</Value1>
> <Value2>2</Value2>
> <Value3>3</Value3>
> </Root>
>
>
>
> Now, I'd like to pass a name of a child element of Root (like Value1
> or Value2) from a Java class into this stylesheet as param
> 'objectname'.
>
> I can pass the parameter fine (I have tested this), but I understand
> that this won't work because the XSLT interpretor cannot resolve the
> value of $objectname as part of an XPath expression representing a
> nodeset.

XPath has a function local-name() so you could have an XPath alike
*[local-name() = $objectname]
to select elements with the name passed in.
--

Martin Honnen
http://JavaScript.FAQTs.com/

Martin Honnen <> wrote in message news:<4010040f$>...
> Colin Toal wrote:
>
>
> > I have a stylesheet like this:
> >
> > <?xml version="1.0" encoding="UTF-8"?>
> > <xsl:stylesheet xmlnssl="http://www.w3.org/1999/XSL/Transform"
> > version="1.0">
> > <xslaram name="objectname"/>
> >
> > <xsl:template match="/Root">
> > <xsl:apply-templates select="./$objectname"/>
> > </xsl:template>
> >
> > <xsl:template match="$objectname">
> > <Result>
> > <xsl:value-of select="."/>
> > </Result>
> > </xsl:template>
> >
> > </xsl:stylesheet>
> >
> > and XML like this:
> >
> > <?xml version="1.0" ?>
> > <Root>
> > <Value1>1</Value1>
> > <Value2>2</Value2>
> > <Value3>3</Value3>
> > </Root>
> >
> >
> >
> > Now, I'd like to pass a name of a child element of Root (like Value1
> > or Value2) from a Java class into this stylesheet as param
> > 'objectname'.
> >
> > I can pass the parameter fine (I have tested this), but I understand
> > that this won't work because the XSLT interpretor cannot resolve the
> > value of $objectname as part of an XPath expression representing a
> > nodeset.
>
> XPath has a function local-name() so you could have an XPath alike
> *[local-name() = $objectname]
> to select elements with the name passed in.

Thank you for the help -

Will that work for 'match' expressions also ?

Colin