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Hi.

Im getting an ArrayIndexOutOfBoundsException when using an array, and
while I know I can use a try catch statement to get around this
problem, I was wondering if there was a way to test to see if the
element exists instead.

for instance.

if (myArray[67].exists){
//then do something with myArray[67]
}

thanks.

I got it

if (67 > myArray.length){
//not exception!
}

tiewknvc9 wrote:
> I got it
>
> if (67 > myArray.length){
> //not exception!
> }

Actually, I think you mean "index < myArray.length". If the index is
greater than the length (or even equal to it), you will get an exception.

Alan Krueger schrieb:
> tiewknvc9 wrote:
>> I got it
>>
>> if (67 > myArray.length){
>> //not exception!
>> }
>
> Actually, I think you mean "index < myArray.length". If the index is
> greater than the length (or even equal to it), you will get an exception.

Be aware, that arrays in Java are zero-based.

A typical loop over an array looks like this:

String[] strings = new String[]{"string0", "string1", "string2"};

// zero-based:
// strings[0] ==> "string0"
// strings[1] ==> "string1"
// strings[2] ==> "string2"
// strings.length == 3

for (int i = 0; i < strings.length; i++) {
String current = strings[i];
// do something with it ...
System.out.println(i + ": " + current);
}

This way you will never get any ArrayIndexOutOfBoundsExceptions ...

Greetings Finomosec;

On Thu, 16 Feb 2006 21:53:25 +0100, Finomosec <>
wrote, quoted or indirectly quoted someone who said :

>Be aware, that arrays in Java are zero-based.

in other words if you have an array of 10 elements ,they are numbered
0 to 9.
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