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public static void sneakyThrow(Throwable t){
Thread.currentThread().stop(t);
}

----It appears that you can throw exception from any point in your
code.
what does it mean?

How and why it bypasses all the exceptions? bypassed where?

it is item 43 in Java Puzzlers.

I am not quite sure what it means.

Can someone elaborate....

puzzlecracker wrote:
> public static void sneakyThrow(Throwable t){
> Thread.currentThread().stop(t);
> }
>
> ----It appears that you can throw exception from any point in your
> code.
> what does it mean?
>
> How and why it bypasses all the exceptions? bypassed where?

Exceptions aren't bypassed, but exception checking is.

For a method (in source code) to be able to throw an exception that does
not extend Error or RuntimeException, a throws clause needs to be
present. The checking is done at compile-time, not at runtime. There are
a number of ways to throw a checked exception from methods that do not
declare that exception, as detailed in the book.

Tom Hawtin
--
Unemployed English Java programmer
http://jroller.com/page/tackline/