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Dear All!!,

I have a problem on my java program. pls help me as i can't find error.

below is my java coding.

import java.io.*;

public class Demo {

static Node objLL;
static BufferedReader br = new BufferedReader (new
InputStreamReader ( System.in));

public static void main (String args[]) throws IOException {

int choice = 0;

do {

System.out.println ("\nDemo:");
System.out.println ("-----\n");
System.out.println ("Press (1) to ADD.");
System.out.println ("Press (2) to VIEW.");
System.out.println ("Press (3) to EXIT.");
System.out.print ("Choice: ");
choice = Integer.parseInt (br.readLine ());

if (choice == 1)
add ();
else if (choice == 2)
view ();

} while (choice != 3);
}

static void add () {

if (objLL == null)
objLL = new Node ();
else {

Node temp = objLL;
while (temp != null)
temp = temp.next;

temp = new Node ();
}

System.out.println ("\nNode added.");
}

static void view () {

if (objLL == null)
System.out.println ("\nNo nodes to display.");
else {

System.out.println ();

int loopCount = 0;
for (loopCount = 1; loopCount <=
objLL.nodeCount; loopCount++)
System.out.println (loopCount);

System.out.println ();
}
}
}

class Node {

public Node next;
static int nodeCount;

Node () {

next = null;
nodeCount++;
}
}


that is program process

when u run the program.............


1.add
2.view
3.exit

enter ur number - 1

enter ur username - aung aung
enter ur ID - 122333
enter ur contact number - 313412415
enter ur genter - m

enter ur number - 2

user name user ID contact number genter
----------------------------------------------------------------------------------------
aungaung 12333 313412415 m

enter ur number - 1

enter ur username - aye
enter ur ID - 22222
enter ur contact number - 22222222
enter ur genter - f

enter ur number - 2

user name user ID contact number genter
----------------------------------------------------------------------------------------
aungaung 12333 313412415 m
aye 22222 222222222 f

enter ur number - 3

program end .........

that is all the process
no need DB and no need array
only simple java code
thx 4 helping me .

Help Me, Pls

You need some variables to store username, id... where are you
declaring them?? I guess you need to declare them as memeber variables
in Node class and in the Node constructor you need to read the values
for these variables.

And override toString() function in Node which will print these values,
so that you can print Node object.

Hello Stephan,

i have modified yr code and made same program that u want...

source code:

import java.io.*;


public class Demo {


static Node objLL;
static BufferedReader br = new BufferedReader (new
InputStreamReader ( System.in));


public static void main (String args[]) throws IOException {


int choice = 0;


do {


System.out.println ("\nDemo:");
System.out.println ("-----\n");
System.out.println ("Press (1) to ADD.");
System.out.println ("Press (2) to VIEW.");
System.out.println ("Press (3) to EXIT.");
System.out.print ("Choice: ");
choice = Integer.parseInt (br.readLine ());


if (choice == 1)
add ();
else if (choice == 2)
view ();


} while (choice != 3);
}


static void add () {


if (objLL == null)
objLL = new Node ();
else {


Node temp = objLL;
while (temp != null)
temp = temp.next;


temp = new Node ();
}
try{
System.out.print ("Enter Username:");
objLL.v1.add((String)br.readLine ());
System.out.print ("Enter Id:");
objLL.v2.add((String)br.readLine ());
System.out.print ("Enter Contact Number:");
objLL.v3.add((String)br.readLine ());
System.out.print ("Enter genter:");
objLL.v4.add((String)br.readLine ());
}catch(Exception e)
{
e.printStackTrace();
}

System.out.println ("\nNode added.");
}


static void view () {


if (objLL == null)
System.out.println ("\nNo nodes to display.");
else {


System.out.println ();


int loopCount = 0;
for (loopCount = 1; loopCount <=
objLL.nodeCount; loopCount++)
System.out.println (loopCount);
System.out.println("user name user ID contact
number genter");
System.out.println("-----------------------------------------------------------------");

for(int i=0;i<objLL.v1.size();i++)
{
System.out.println((String)objLL.v1.get(i) + "\t\t\t"
+(String)objLL.v2.get(i)+"\t\t\t"+(String)objLL.v3 .get(i)+"\t\t\t"+(String)objLL.v4.get(i));
}
System.out.println ();
}


}



}


class Node {

public Node next;
static int nodeCount;
java.util.Vector v1 = new java.util.Vector();
java.util.Vector v2 = new java.util.Vector();
java.util.Vector v3 = new java.util.Vector();
java.util.Vector v4 = new java.util.Vector();

Node () {


next = null;
nodeCount++;
}



}

Hello Stephan,

i have modified yr code and made same program that u want...

source code:

import java.io.*;


public class Demo {


static Node objLL;
static BufferedReader br = new BufferedReader (new
InputStreamReader ( System.in));


public static void main (String args[]) throws IOException {


int choice = 0;


do {


System.out.println ("\nDemo:");
System.out.println ("-----\n");
System.out.println ("Press (1) to ADD.");
System.out.println ("Press (2) to VIEW.");
System.out.println ("Press (3) to EXIT.");
System.out.print ("Choice: ");
choice = Integer.parseInt (br.readLine ());


if (choice == 1)
add ();
else if (choice == 2)
view ();


} while (choice != 3);
}


static void add () {


if (objLL == null)
objLL = new Node ();
else {


Node temp = objLL;
while (temp != null)
temp = temp.next;


temp = new Node ();
}
try{
System.out.print ("Enter Username:");
objLL.v1.add((String)br.readLine ());
System.out.print ("Enter Id:");
objLL.v2.add((String)br.readLine ());
System.out.print ("Enter Contact Number:");
objLL.v3.add((String)br.readLine ());
System.out.print ("Enter genter:");
objLL.v4.add((String)br.readLine ());
}catch(Exception e)
{
e.printStackTrace();
}

System.out.println ("\nNode added.");
}


static void view () {


if (objLL == null)
System.out.println ("\nNo nodes to display.");
else {


System.out.println ();


int loopCount = 0;
for (loopCount = 1; loopCount <=
objLL.nodeCount; loopCount++)
System.out.println (loopCount);
System.out.println("user name user ID contact
number genter");
System.out.println("-----------------------------------------------------------------");

for(int i=0;i<objLL.v1.size();i++)
{
System.out.println((String)objLL.v1.get(i) + "\t\t\t"
+(String)objLL.v2.get(i)+"\t\t\t"+(String)objLL.v3 .get(i)+"\t\t\t"+(String)objLL.v4.get(i));
}
System.out.println ();
}


}



}


class Node {

public Node next;
static int nodeCount;
java.util.Vector v1 = new java.util.Vector();
java.util.Vector v2 = new java.util.Vector();
java.util.Vector v3 = new java.util.Vector();
java.util.Vector v4 = new java.util.Vector();

Node () {


next = null;
nodeCount++;
}



}

Hello Stephan,

i have modified yr code and made same program that u want...

source code:

import java.io.*;


public class Demo {


static Node objLL;
static BufferedReader br = new BufferedReader (new
InputStreamReader ( System.in));


public static void main (String args[]) throws IOException {


int choice = 0;


do {


System.out.println ("\nDemo:");
System.out.println ("-----\n");
System.out.println ("Press (1) to ADD.");
System.out.println ("Press (2) to VIEW.");
System.out.println ("Press (3) to EXIT.");
System.out.print ("Choice: ");
choice = Integer.parseInt (br.readLine ());


if (choice == 1)
add ();
else if (choice == 2)
view ();


} while (choice != 3);
}


static void add () {


if (objLL == null)
objLL = new Node ();
else {


Node temp = objLL;
while (temp != null)
temp = temp.next;


temp = new Node ();
}
try{
System.out.print ("Enter Username:");
objLL.v1.add((String)br.readLine ());
System.out.print ("Enter Id:");
objLL.v2.add((String)br.readLine ());
System.out.print ("Enter Contact Number:");
objLL.v3.add((String)br.readLine ());
System.out.print ("Enter genter:");
objLL.v4.add((String)br.readLine ());
}catch(Exception e)
{
e.printStackTrace();
}

System.out.println ("\nNode added.");
}


static void view () {


if (objLL == null)
System.out.println ("\nNo nodes to display.");
else {


System.out.println ();


int loopCount = 0;
for (loopCount = 1; loopCount <=
objLL.nodeCount; loopCount++)
System.out.println (loopCount);
System.out.println("user name user ID contact
number genter");
System.out.println("-----------------------------------------------------------------");

for(int i=0;i<objLL.v1.size();i++)
{
System.out.println((String)objLL.v1.get(i) + "\t\t\t"
+(String)objLL.v2.get(i)+"\t\t\t"+(String)objLL.v3 .get(i)+"\t\t\t"+(String)objLL.v4.get(i));
}
System.out.println ();
}


}



}


class Node {

public Node next;
static int nodeCount;
java.util.Vector v1 = new java.util.Vector();
java.util.Vector v2 = new java.util.Vector();
java.util.Vector v3 = new java.util.Vector();
java.util.Vector v4 = new java.util.Vector();

Node () {


next = null;
nodeCount++;
}



}