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"moon" <> wrote in message
news: m...
> Hi Andrew,
> sorry i didnt mention what i was trying to do. i want to display all
> the cards in a deck..so for example, it should print out: ace of
> clubs, two of clubs, three of clubs, ace of spades, two of spades,
> etc...
-----------------
change 20 to 52 in the 'for' loop at the bottom
this does what you want
sample output
---
7 of Hearts
2 of Diamonds
9 of Diamonds
Queen of Clubs
King of Diamonds
8 of Hearts
3 of Diamonds
Queen of Diamonds
6 of Diamonds
Jack of Hearts
Jack of Diamonds
10 of Diamonds
3 of Spades
Queen of Hearts
Jack of Clubs
2 of Hearts
5 of Clubs
Queen of Spades
5 of Spades
7 of Clubs
---
-----------------
// program that prints 20 random cards
//
// Here is a solution from the master of collections himself,
// Joshua Bloch.
// Mon Oct 6 00:39:19 CDT 2003

import java.util.ArrayList;
import java.util.Collections;
import java.util.List;

class Deal {
public static void main(String args[]) {
// Make a standard 52-card deck
String[] suit =
new String[] { "Spades", "Hearts", "Diamonds", "Clubs" };
String[] rank =
new String[] {
" Ace",
" 2",
" 3",
" 4",
" 5",
" 6",
" 7",
" 8",
" 9",
" 10",
" Jack",
"Queen",
" King" };
List deck = new ArrayList();
for (int i = 0; i < suit.length; i++) {
for (int j = 0; j < rank.length; j++) {
deck.add(rank[j] + " of " + suit[i]);
}
}
Collections.shuffle(deck);
for (int j = 0; j < 20; j++) {
System.out.println(deck.get(j));
}
}
}

Moon,
Andrew treats everyone that way. I have been programming for 26 years
in 6 or 7 languages -- I used to prefer basic, now I prefer Java. I
have been posting to newsgroups for as long as I can remember. I used
to bottom post (when posts were tiny), now I top post. It's all good.

moon wrote:
> Well, thanks for taking the time to patronize. I have been posting
> questions in various groups but have not come across anything like
> this. I am a newbie but everyone starts out shaky and theres no need
> to be so demanding. Sorry for wasting everyone's time here.
> moon

On 3 Mar 2004 15:35:20 -0800, Gregory A. Swarthout wrote:
> Just an observation, but a normal deck of cards has 13 ranks, not
> 12.

Here's another observation: there are 13 values from 0-12 (inclusive).

moon wrote:
> for(int j = 0; j < 12; j++)

/gordon

--
[ do not email me copies of your followups ]
g o r d o n + n e w s @ b a l d e r 1 3 . s e

Gordon Beaton <> wrote in message news:<4046f1ed$>...
> On 3 Mar 2004 15:35:20 -0800, Gregory A. Swarthout wrote:
> > Just an observation, but a normal deck of cards has 13 ranks, not
> > 12.
>
> Here's another observation: there are 13 values from 0-12 (inclusive).
>
> moon wrote:
> > for(int j = 0; j < 12; j++)
>
> /gordon

*Sigh*

A further observation:

j < 12 means that only values 0-11 will be used. Ergo, use j <= 12 or
j < 13.

Greg