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Increase value in hash table
Hi Al
I have Data file have below Data file V1 V2 V3 V4 V4 V3 How to using count number of data ? Output V1 = 1 V2 = 1 V3 =2 V4 = 2 # Global Veriable printque = {} in def have below printque[val] = printque[val] + 1 I have below error File "xprintlogchk.py", line 78, in chklog printque[val] = printque[val] + 1 KeyError: 'nan' |
Re: Increase value in hash table
On Jan 22, 2013 11:31 PM, "moonhkt" <moonhkt@gmail.com> wrote:
> > Hi Al > > I have Data file have below > > Data file > V1 > V2 > V3 > V4 > V4 > V3 > > How to using count number of data ? > > Output > V1 = 1 > V2 = 1 > V3 =2 > V4 = 2 Construct a frequency table using collections.Counter: http://docs.python.org/2.7/library/c...ctions.Counter |
Re: Increase value in hash table
On Jan 23, 3:34*pm, Chris Rebert <c...@rebertia.com> wrote:
> On Jan 22, 2013 11:31 PM, "moonhkt" <moon...@gmail.com> wrote: > > > > > > > > > > > > > Hi Al > > > I have Data file have below > > > Data file > > V1 > > V2 > > V3 > > V4 > > V4 > > V3 > > > How to using count number of data ? > > > Output > > V1 = 1 > > V2 = 1 > > V3 =2 > > V4 = 2 > > Construct a frequency table using collections.Counter: > > http://docs.python.org/2.7/library/c...ctions.Counter What is problem for below ? #!/usr/bin/env python # Python hash {} # Python Lists [] global age karry = "ER" k1 = "EU" age = {} age[karry] = 3 age[k1] = 5 def ABC(): global age global karry i = 0 a = "A B" karry = a.split() age[karry[0]] += 1 ABC() for key in age: print key, age[key] Result ex_array.py Traceback (most recent call last): File "ex_array.py", line 21, in <module> ABC() File "ex_array.py", line 18, in ABC age[karry[0]] += 1 KeyError: 'A' |
Re: Increase value in hash table
On 23 January 2013 07:26, moonhkt <moonhkt@gmail.com> wrote:
> Hi Al > > I have Data file have below > > Data file > V1 > V2 > V3 > V4 > V4 > V3 > > How to using count number of data ? > > Output > V1 = 1 > V2 = 1 > V3 =2 > V4 = 2 > > > > # Global Veriable > printque = {} > in def have below > > printque[val] = printque[val] + 1 > > I have below error > File "xprintlogchk.py", line 78, in chklog > printque[val] = printque[val] + 1 > KeyError: 'nan' You can't retrieve the value of printque[val] if you haven't yet added an entry with the key val to the dict. Try this: if val not in printque: printque[val] = 1 else: printque[val] = printque[val] + 1 Oscar |
Re: Increase value in hash table
On Wed, 23 Jan 2013 10:12:25 +0000, Oscar Benjamin wrote:
> You can't retrieve the value of printque[val] if you haven't yet added > an entry with the key val to the dict. Try this: > > if val not in printque: > printque[val] = 1 > else: > printque[val] = printque[val] + 1 Another way of writing that is: printque[val] = printque.get(val, 0) + 1 -- Steven |
Re: Increase value in hash table
On Wed, 23 Jan 2013 10:12:25 +0000, Oscar Benjamin wrote:
> You can't retrieve the value of printque[val] if you haven't yet added > an entry with the key val to the dict. Try this: > > if val not in printque: > printque[val] = 1 > else: > printque[val] = printque[val] + 1 Another way of writing that is: printque[val] = printque.get(val, 0) + 1 -- Steven |
Re: Increase value in hash table
On Wed, 23 Jan 2013 10:12:25 +0000, Oscar Benjamin wrote:
> You can't retrieve the value of printque[val] if you haven't yet added > an entry with the key val to the dict. Try this: > > if val not in printque: > printque[val] = 1 > else: > printque[val] = printque[val] + 1 Another way of writing that is: printque[val] = printque.get(val, 0) + 1 -- Steven |
Re: Increase value in hash table
On Wed, 23 Jan 2013 10:12:25 +0000, Oscar Benjamin wrote:
> You can't retrieve the value of printque[val] if you haven't yet added > an entry with the key val to the dict. Try this: > > if val not in printque: > printque[val] = 1 > else: > printque[val] = printque[val] + 1 Another way of writing that is: printque[val] = printque.get(val, 0) + 1 -- Steven |
Multiple postings [was Re: Increase value in hash table]
Steven D'Aprano wrote:
[snip content] Arrgggh, it's happened again. Sorry for the multiple posts folks, I *swear* I only sent it once. Trying this time with a different news client. -- Steven |
Re: Multiple postings [was Re: Increase value in hash table]
On Jan 23, 3:54*pm, Steven D'Aprano <steve
+comp.lang.pyt...@pearwood.info> wrote: > Steven D'Aprano wrote: > > I *swear* I only sent it once. Now Now Steven! Good boys dont swear. > Arrgggh, it's happened again. Sorry for the multiple posts folks... > Trying this time with a different news client. Its a law of the universe called karma. Thou shalt double triple quadruple post for each GG user thou tickest off. And the choice for instant liberation is always there: Use GG!! |
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