Re: Windows subprocess.call problem
email@example.com had an excellent suggestion that worked right off the
bat and achieved exactly what I was after. Thanks all!
On Mon, Jan 21, 2013 at 9:04 AM, Dave Angel <firstname.lastname@example.org> wrote:
> On 01/21/2013 06:25 AM, Tom Borkin wrote:
>> I have this code:
>> for song in my_songs:
>> subprocess.call(['notepad.exe'**, '%s.txt' % song])
>> print song
>> It opens the first song and hangs on subsequent songs. It doesn't open the
>> next song or execute the print until I have closed the first one. I want
>> to open all in the list, one after another, so I have all those songs
>> available. Please advise.
> Why not just pass all the filenames as parameters in one invocation of
> notepad? Assuming Notepad is written reasonably, that'll give it all to
> you in one window, instead of opening many separate ones.
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