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- - **Floating Point Representation (Question)**
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Floating Point Representation (Question)AFAIK 0.1 in hex is 0x1.(9)ap-4, where »(9)« means an
infinite sequence of »9«. However, Java only stores a finite number of 9s: printf( "%a%n", 0.1 ) 0x1.999999999999ap-4 . So, since something /positive/ is missing, Javas representation of 0.1 should be /smaller/ than 0.1, but println( new java.math.BigDecimal( 0.1 )) 0.100000000000000005551115123125782702118158340454 1015625 shows me a value that is /greater/ than 0.1? Removing more 9s makes the value even larger! println( new java.math.BigDecimal( 0x1.999999999999ap-4 )); 0.100000000000000005551115123125782702118158340454 1015625 println( new java.math.BigDecimal( 0x1.9ap-4 )) 0.10009765625 |

Re: Floating Point Representation (Question)Patricia Shanahan <pats@acm.org> writes:
>The "a" in "0x1.999999999999ap-4" is the last digit of the hex fraction. For some reason, I did not understand this, but thought »ap« was a unit marking the start of the exponent (already wondering »Why /two/ letters?«). Now that you have told me this, I understand it all - thank you! |

Re: Floating Point Representation (Question)On 12/26/2012 11:22 AM, Stefan Ram wrote:
> AFAIK 0.1 in hex is 0x1.(9)ap-4, where »(9)« means an > infinite sequence of »9«. What's the "a" for? ;-) > However, Java only stores a > finite number of 9s: > > printf( "%a%n", 0.1 ) > 0x1.999999999999ap-4 "One, point, twelve nines, A, exponent." See the "A?" -- Eric Sosman esosman@comcast-dot-net.invalid |

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