Re: forking and avoiding zombies!
2012/12/11 Jean-Michel Pichavant <email@example.com>:
> ----- Original Message -----
>> So I implemented a simple decorator to run a function in a forked
>> process, as below.
>> It works well but the problem is that the childs end up as zombies on
>> one machine, while strangely
>> I can't reproduce the same on mine..
>> I know that this is not the perfect method to spawn a daemon, but I
>> also wanted to keep the code
>> as simple as possible since other people will maintain it..
>> What is the easiest solution to avoid the creation of zombies and
>> maintain this functionality?
>> def on_forked_process(func):
>> from os import fork
>> """Decorator that forks the process, runs the function and gives
>> back control to the main process
>> def _on_forked_process(*args, **kwargs):
>> pid = fork()
>> if pid == 0:
>> func(*args, **kwargs)
>> return pid
>> return _on_forked_process
> Ever though about using the 'multiprocessing' module? It's a slightly higher API and I don't have issues with zombie processes.
> You can combine this with a multiprocess log listener so that all logs are sent to the main process.
> See Vinay Sajip's code about multiprocessing and logging, http://plumberjack.blogspot.fr/2010/...rocessing.html
> I still had to write some cleanup code before leaving the main process, but once terminate is called on all remaining subprocesses, I'm not left with zombie processes.
> Here's the cleaning:
> for proc in multiprocessing.active_children():
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Yes I thought about that but I want to be able to kill the parent
without killing the childs, because they can run for a long time..
Anyway I got something working now with this
def _daemonize(*args, **kwargs):
# Perform first fork.
pid = os.fork()
if pid > 0:
sys.exit(0) # Exit first parent.
except OSError as e:
sys.stderr.write("fork #1 failed: (%d) %s\n" % (e.errno,
# Decouple from parent environment.
# check if decoupling here makes sense in our case
# Perform second fork.
pid = os.fork()
if pid > 0:
except OSError, e:
sys.stderr.write("fork #2 failed: (%d) %s\n" % (e.errno,
# The process is now daemonized, redirect standard file descriptors..
print("Hello how are you?")
And it works exactly as before, but more correctly..
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