Re: [Q] How to exec code object with local variables specified?
 

Makoto Kuwata wrote:

> Is it possible to run code object with local variables specified?
> I'm trying the following code but not work:
>
> def fn():
> x = 1
> y = 2
> localvars = {'x': 0}
> exec(fn.func_code, globals(), localvars)
> print(localvars)
> ## what I expected is: {'x': 1, 'y': 2}
> ## but actual is: {'x': 0}
>
> Python: 2.7.3

>>> loc = {}
>>> exec("x = 1; y = 2", globals(), loc)
>>> loc
{'y': 2, 'x': 1}

However, this won't work with the code object taken from a function which
uses a different a bytecode (STORE_FAST instead of STORE_NAME):


>>> import dis
>>> def f(): x = 1
....
>>> dis.dis(f)
1 0 LOAD_CONST 1 (1)
3 STORE_FAST 0 (x)
6 LOAD_CONST 0 (None)
9 RETURN_VALUE
>>> dis.dis(compile("x=1", "<nofile>", "exec"))
1 0 LOAD_CONST 0 (1)
3 STORE_NAME 0 (x)
6 LOAD_CONST 1 (None)
9 RETURN_VALUE