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-   -   Re: A little morning puzzle (http://www.velocityreviews.com/forums/t952413-re-a-little-morning-puzzle.html)

Dwight Hutto 09-19-2012 12:22 PM

Re: A little morning puzzle
 
On Wed, Sep 19, 2012 at 8:01 AM, Dwight Hutto <dwightdhutto@gmail.com> wrote:
>> I have a list of dictionaries. They all have the same keys. I want to find the
>> set of keys where all the dictionaries have the same values. Suggestions?

>

This one is better:


a = {}
a['dict'] = 1

b = {}
b['dict'] = 2

c = {}
c['dict'] = 1

d = {}
d['dict'] = 3

e = {}
e['dict'] = 1


x = [a,b,c,d,e]
count = 0
collection_count = 0
search_variable = 1
for dict_key_search in x:
if dict_key_search['dict'] == search_variable:
print "Match count found: #%i = %i" % (count,search_variable)
collection_count += 1
count += 1
print collection_count

--
Best Regards,
David Hutto
CEO: http://www.hitwebdevelopment.com


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