Default type for "register" variable
 

When the type specifier is missing for variable "register i", what's the
default type assumed in C?

int redian(int Max)
{
register i;

for (i = 1; i <= Max; i++)
...
}

Re: Default type for "register" variable
 

On Sep 1, 3:24 pm, "ose" <os...@hotmail.com> wrote:
> When the type specifier is missing for variable "register i", what's the
> default type assumed in C?
>
> int redian(int Max)
> {
> register i;
>
> for (i = 1; i <= Max; i++)
> ...
>
> }

The type defaults to int in C89, in C99 it is an error.

Robert Gamble

Re: Default type for "register" variable
 

"Robert Gamble" <rgamble99@gmail.com> wrote in message
news:1188675285.292033.316730@57g2000hsv.googlegro ups.com...
> On Sep 1, 3:24 pm, "ose" <os...@hotmail.com> wrote:
>> When the type specifier is missing for variable "register i", what's the
>> default type assumed in C?
>>
>> int redian(int Max)
>> {
>> register i;
>>
>> for (i = 1; i <= Max; i++)
>> ...
>>
>> }
>
> The type defaults to int in C89, in C99 it is an error.
>
That could be a way of getting rid of size_t. Default to a size_t in C 2007.

--
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http://www.personal.leeds.ac.uk/~bgy1mm

Re: Default type for "register" variable
 

>>> When the type specifier is missing for variable "register i", what's the
>>> default type assumed in C?
>>>
>>> int redian(int Max)
>>> {
>>> register i;
>>>
>>> for (i = 1; i <= Max; i++)
>>> ...
>>>
>>> }
>>
>> The type defaults to int in C89, in C99 it is an error.
>>
>That could be a way of getting rid of size_t. Default to a size_t in C 2007.

Why would you want to make that a default type? Why not something
more useful, say, a function pointer? Or an array of 3 doubles?

In any case, it's preferable to explicitly state the type, as
otherwise you have silent breakage if the code is compiled with an
older version of C.