Velocity Reviews - xslt not working when xml has xmlns="urn" in root element.

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xslt not working when xml has xmlns="urn" in root element.

Hello guys, I am new to XML and working on a XSLT to transforn yahoo
shopping search result to html. my problem is the return XML contain
xmlns in root element, here is the sample xml:

<?xml version="1.0" encoding="UTF-8"?>
<?xml-stylesheet type="text/xsl" href="aproductsearch.xslt"?>
<ProductSearch xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="urn:yahoo:aprods" xsi:schemaLocation="urn:yahoo:aprods
http://api.shopping.yahoo.com/shoppingservice/v2/aproductsearch.xsd">
...................
</ProductSearch>

I am testing my xslt file:

<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="html" encoding="utf-8" omit-xml-
declaration="yes"
indent="yes"/>

<xsl:template match="/">
<HTML>
<BODY>
<TABLE BORDER="2">
<TR>
<TD>From</TD>
<TD>To</TD>
</TR>
<xsl:for-each select="ProductSearch/
Products/Product">
<TR>
<TD>
<xsl:value-of
select="Catalog/PriceFrom"/>
</TD>
<TD>
<xsl:value-of
select="Catalog/PriceTo"/>
</TD>
</TR>
</xsl:for-each>
</TABLE>
</BODY>
</HTML>
</xsl:template>

</xsl:stylesheet>

if I remove the xmlns="urn:yahoo:aprods" from the XML, then the xslt
works fine, otherwise, nothing shows up. I don't know what is the
problem of my xslt file.

Thanks a lot!

Re: xslt not working when xml has xmlns="urn" in root element.

On Apr 3, 9:09 pm, "Lee" <lee.jenkins...@gmail.com> wrote:
> <?xml version="1.0" encoding="UTF-8"?>
> <?xml-stylesheet type="text/xsl"
> href="aproductsearch.xslt"?>
> <ProductSearch
> xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
> xmlns="urn:yahoo:aprods"
> xsi:schemaLocation=
> "urn:yahoo:aprodshttp://api.shopping.yahoo.com/shoppingservice/v2/aproductsearch.xsd">
> ..................
> </ProductSearch>
>
> <?xml version="1.0" encoding="utf-8"?>
> <xsl:stylesheet version="1.0"
> xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
> <xsl:output method="html" encoding="utf-8"
> omit-xml-declaration="yes" indent="yes"/>
> <xsl:template match="/">
> <HTML>
> <BODY>
> <TABLE BORDER="2">
> <TR>
> <TD>From</TD>
> <TD>To</TD>
> </TR>
> <xsl:for-each
> select="ProductSearch/Products/Product">
> <TR>
> <TD>
> <xsl:value-of select="Catalog/PriceFrom"/>
> </TD>
> <TD>
> <xsl:value-of select="Catalog/PriceTo"/>
> </TD>
> </TR>
> </xsl:for-each>
> </TABLE>
> </BODY>
> </HTML>
> </xsl:template>
> </xsl:stylesheet>

Using tabs or 8 spaces for indentation on the usenet is not
particularly wise.

> if I remove the xmlns="urn:yahoo:aprods" from the XML,
> then the xslt works fine, otherwise, nothing shows up. I
> don't know what is the problem of my xslt file.

What did you expect? ProductSearch element in the XML
document you've provided is really
{urn:yahoo:aprods}ProductSearch, and you're selecting
{}ProductSearch elements in your for-each. Consider reading
some introductory material on XML Namespaces overall and on
using XML Namespaces in XSL Transformations in particular.

--
Pavel Lepin

Re: xslt not working when xml has xmlns="urn" in root element.

Lee wrote:

> <ProductSearch xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
> xmlns="urn:yahoo:aprods" xsi:schemaLocation="urn:yahoo:aprods
> http://api.shopping.yahoo.com/shoppingservice/v2/aproductsearch.xsd">
> ..................
> </ProductSearch>

> <xsl:stylesheet version="1.0"
> xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

Add
xmlns:ap="urn:yahoo:aprods"
on the xsl:stylesheet element, then use the prefix 'ap' in your XPath
expressions e.g.

> <xsl:for-each select="ProductSearch/
> Products/Product">

<xsl:for-each select="ap:ProductSearch/ap:Products/ap:Product">

> <xsl:value-of
> select="Catalog/PriceFrom"/>

<xsl:value-of select="ap:Catalog/ap:PriceForm">

> <xsl:value-of
> select="Catalog/PriceTo"/>

<xsl:value-of select="ap:Catalog/ap:PriceTo"/>

--

Martin Honnen
http://JavaScript.FAQTs.com/

Re: xslt not working when xml has xmlns="urn" in root element.

On Apr 4, 4:37 am, Martin Honnen <mahotr...@yahoo.de> wrote:
> Lee wrote:
> > <ProductSearch xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
> > xmlns="urn:yahoo:aprods" xsi:schemaLocation="urn:yahoo:aprods
> >http://api.shopping.yahoo.com/shoppingservice/v2/aproductsearch.xsd">
> > ..................
> > </ProductSearch>
> > <xsl:stylesheet version="1.0"
> > xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
>
> Add
> xmlns:ap="urn:yahoo:aprods"
> on the xsl:stylesheet element, then use the prefix 'ap' in your XPath
> expressions e.g.
>
> > <xsl:for-each select="ProductSearch/
> > Products/Product">
>
> <xsl:for-each select="ap:ProductSearch/ap:Products/ap:Product">
>
> > <xsl:value-of
> > select="Catalog/PriceFrom"/>
>
> <xsl:value-of select="ap:Catalog/ap:PriceForm">
>
> > <xsl:value-of
> > select="Catalog/PriceTo"/>
>
> <xsl:value-of select="ap:Catalog/ap:PriceTo"/>
>
> --
>
> Martin Honnen
> http://JavaScript.FAQTs.com/

Thanks a lot, it works fine now. thanks for the help.