How to understand this line of c ?
 

main(_){for(--_;putchar(_++["J!Mpwf!Zpv\1"]-1););}

Re: How to understand this line of c ?
 

"lnzju" <geniuslee@gmail.com> wrote in message
news:1136051664.299850.274430@g43g2000cwa.googlegr oups.com...
> main(_){for(--_;putchar(_++["J!Mpwf!Zpv\1"]-1););}
>

Don't. It's rubbish.


--
Ivan Budiselic
ICQ# 104044323
IRC: buda @ #gamer.hr@quakenet
remove 'remove' for reply

Re: How to understand this line of c ?
 

lnzju wrote:
> main(_){for(--_;putchar(_++["J!Mpwf!Zpv\1"]-1););}

Some hints:

* Write the program with the correct tabulation
* Take into account that usually main parameters are argc and argv, but
they can be called with any name. And, if type is not declared K&R
assumes int.
* _ can be the name of a variable.
* Split "for" in its parts: a for statement is divided in
initialization, continue condition and update of state. The first one
and third ones can be empty.
* putchar returns the character written as unsigned int
* integer applied to string returns n-th element. (this is something I
do not know why).

Kind regards.

Re: How to understand this line of c ?
 

Ivan Budiselic wrote:

> "lnzju" <geniuslee@gmail.com> wrote in message
> news:1136051664.299850.274430@g43g2000cwa.googlegr oups.com...
>> main(_){for(--_;putchar(_++["J!Mpwf!Zpv\1"]-1););}
>>
>
> Don't. It's rubbish.
>
>

Well it ain't rubbish cause it is valid C!!
Try compiling it..

The output will be:

I Love You

But this code is obfuscated.... Only the real C gurus will understand it
I Guess.... not this novice guy...

Broeisi

Re: How to understand this line of c ?
 

Even when "gcc" compiled with the flags -ansi and -pedantic, it
produces no errors nor warnings. Only with -std=c99 it produces 3
warnings.

Re: How to understand this line of c ?
 

Broeisi wrote:
> Ivan Budiselic wrote:
>
>> "lnzju" <geniuslee@gmail.com> wrote in message
>> news:1136051664.299850.274430@g43g2000cwa.googlegr oups.com...
>>> main(_){for(--_;putchar(_++["J!Mpwf!Zpv\1"]-1););}
>>>
>> Don't. It's rubbish.
>
> Well it ain't rubbish cause it is valid C!!

Actually, it's not. In C main either takes no arguments or two
arguments, not 1.

> Try compiling it..
>
> The output will be:
>
> I Love You

Not necessarily. It was written assuming ASCII, and not all C
implementations use ASCII.

> But this code is obfuscated.... Only the real C gurus will understand it
> I Guess.... not this novice guy...

Depends. It's not that difficult. Just format it properly and learn a
couple of tricks and it is simple.
--
Flash Gordon
Living in interesting times.
Although my email address says spam, it is real and I read it.

Re: How to understand this line of c ?
 

"Broeisi" <broeisito@gmail.com> wrote in message
news:Q-CdnbFfZLrCSCvenZ2dnUVZ8qSdnZ2d@casema.nl...
> Ivan Budiselic wrote:
>
>> "lnzju" <geniuslee@gmail.com> wrote in message
>> news:1136051664.299850.274430@g43g2000cwa.googlegr oups.com...
>>> main(_){for(--_;putchar(_++["J!Mpwf!Zpv\1"]-1););}
>>>
>>
>> Don't. It's rubbish.
>>
>>
>
> Well it ain't rubbish cause it is valid C!!
> Try compiling it..
>
> The output will be:
>
> I Love You

Maybe on your machine. Certainly not on all.

> But this code is obfuscated.... Only the real C gurus will understand it
> I Guess.... not this novice guy...
>

There's nothing guruesque about it.

--
Ivan Budiselic
ICQ# 104044323
IRC: buda @ #gamer.hr@quakenet
remove 'remove' for reply

Re: How to understand this line of c ?
 

"lnzju" <geniuslee@gmail.com> wrote in message
news:1136051664.299850.274430@g43g2000cwa.googlegr oups.com...
> main(_){for(--_;putchar(_++["J!Mpwf!Zpv\1"]-1););}

Here it is a little clearer [hopefully?]

#include <stdio.h>

// x will be 1 (the name of this app would be in argv[0]) if we
// don't invoke the app with some args.
//
main(x)
{
char c;

// zero then!
//
--x;

while(c = "J!Mpwf!Zpv\1"[x])
{
// No need for the -1 if we add 1 to the literal's characters...
//
// "I Love You\1"
//
c = c - 1;

x++;

putchar(c);
}
}

Re: How to understand this line of c ?
 

"lnzju" <geniuslee@gmail.com> wrote in message
news:1136051664.299850.274430@g43g2000cwa.googlegr oups.com...
> main(_){for(--_;putchar(_++["J!Mpwf!Zpv\1"]-1););}
>

Ah, but run it with some params, and it's dissapointing. Perhaps the
initialiser in the for loop would have been better this way?

for(_^=_; putchar(_++["J!Mpwf!Zpv\1"]-1); );

Re: How to understand this line of c ?
 

"lnzju" <geniuslee@gmail.com> wrote:
>main(_){for(--_;putchar(_++["J!Mpwf!Zpv\1"]-1););}

The two following code fragments are equivalent:

/*-A-----------------------------------*/

#include <stdio.h>

int main(void)
{
char rubbish[] = "J!Mpwf!Zpv\1"; /* will 'print' trailing '\0' */
char *rp = rubbish;

while (*rp)
{
putchar ((*rp)-1);
rp++;
}
putchar('\n'); /* not in original code */
}

/*-B-----------------------------------*/

#include <stdio.h>

int main(void)
{
char rubbish[] = "I Love You\0"; /* '\0' is redundant here */
char *rp = rubbish;

while (*rp)
{
putchar(*rp);
rp++;
}
putchar('\n'); /* not in original code */
}

/*-------------------------------------*/