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 jeff@foundrymusic.com 12-20-2004 08:15 PM

convert form byte[4] to Int32 while retaining the binary value of the byte array

how do you convert form byte[4] to Int32 while retaining the binary
value of the byte array

 Victor Bazarov 12-20-2004 08:31 PM

Re: convert form byte[4] to Int32 while retaining the binary valueof the byte array

jeff@foundrymusic.com wrote:
> how do you convert form byte[4] to Int32 while retaining the binary
> value of the byte array

First of all, you have to be a bit more specific. For example, you need
to say that your 'byte' has only 8 bits and your Int32 is (probably) 32
bits long. Second, what does "binary value" mean? Is your 'byte' type
signed or unsigned? Third, what do you mean by "convert"? An array of
four chars (signed or unsigned) cannot be _converted_ to a single int in
C++ sense, so you probably mean "how to form a 32-bit value out of 4 8-bit
values and retain the bit pattern of each of 4 source values?" That can
be answered but you need to specify where your 'byte[0]' should go, to the
beginning or to the end of the resulting integer.

See what I mean? Perhaps while trying to understand what you need, you
will find a decent way to "convert" what you need into what you desire
using << and | operators...

What are you trying to accomplish, anyway?

V

 Howard 12-20-2004 08:36 PM

Re: convert form byte[4] to Int32 while retaining the binary value of the byte array

<jeff@foundrymusic.com> wrote in message
> how do you convert form byte[4] to Int32 while retaining the binary
> value of the byte array
>

As far as I know, neither "Int32" nor "byte" are defined as types in C++. I
can *guess* how they're defined, but it's only an eductated guess. What do
you mean when you say you want to "retain the binary value"? And in what
way do you want to "convert" the value?

If what you have is an array of 4 8-bit unsigned char values, and you want
to interpret them as a 32-bit signed long, then one way might be to use a
pointer, like this:

unsigned char array[4];
//.. fill that array somehow...

long* pInt32 = (long*)(&array[0]);

Now, *pInt32 will be interpreted as a signed long.

BUT!!! This may not work on your machine! For one thing, the byte ordering
of the bytes in the array may not be correct for an integer representation
on your machine. On a PC, the ordering of bytes is opposite what it is on
the Mac, for example. It all depends upon you KNOWING that the values in
that array are in the correct order in the first place.

(On the other hand, if you know that they're in the OPPOSITE order, you can
always copy them to another array in reverse order, and then do the above!)

There may be other issues, possibly, such as the size of a char and a long
on your machine, and the possibility that you could put some bit pattern
into that array which would not be a valid 32-bit long integer.

In general, it's best to avoid doing this if possible. But, you can try it
and see if it works for you. Remember, though, that the solution likely
won't be portable across machines.

-Howard

 Jonathan Mcdougall 12-20-2004 08:56 PM

Re: convert form byte[4] to Int32 while retaining the binary valueof the byte array

Howard wrote:
> <jeff@foundrymusic.com> wrote in message
>
>>how do you convert form byte[4] to Int32 while retaining the binary
>>value of the byte array
>>

>
> As far as I know, neither "Int32" nor "byte" are defined as types in C++. I
> can *guess* how they're defined, but it's only an eductated guess. What do
> you mean when you say you want to "retain the binary value"? And in what
> way do you want to "convert" the value?
>
> If what you have is an array of 4 8-bit unsigned char values, and you want
> to interpret them as a 32-bit signed long, then one way might be to use a
> pointer, like this:

<snip..>

Int32 convert(Byte b[4])
{
return (b[0] << 24) | (b[1] << 16) | (b[2] << 8) | (b[3]);
}

Byte b[4] = { 1, 2, 3, 4 };

Int32 i = convert(b);

Let's not get _that_ picky, people.

Jonathan

 Victor Bazarov 12-20-2004 09:04 PM

Re: convert form byte[4] to Int32 while retaining the binary valueof the byte array

Jonathan Mcdougall wrote:
> Howard wrote:
>
>> <jeff@foundrymusic.com> wrote in message
>>
>>> how do you convert form byte[4] to Int32 while retaining the binary
>>> value of the byte array
>>>

>>
>> As far as I know, neither "Int32" nor "byte" are defined as types in
>> C++. I can *guess* how they're defined, but it's only an eductated
>> guess. What do you mean when you say you want to "retain the binary
>> value"? And in what way do you want to "convert" the value?
>>
>> If what you have is an array of 4 8-bit unsigned char values, and you
>> want to interpret them as a 32-bit signed long, then one way might be
>> to use a pointer, like this:

>
>
> <snip..>
>
> Int32 convert(Byte b[4])
> {
> return (b[0] << 24) | (b[1] << 16) | (b[2] << 8) | (b[3]);
> }
>
> Byte b[4] = { 1, 2, 3, 4 };
>
> Int32 i = convert(b);
>
>
> Let's not get _that_ picky, people.

How did you know the OP didn't want

return (b[3] << 24) | (b[2] << 16) | (b[1] << 8) | (b[0]);

???

V

 Howard 12-20-2004 09:08 PM

Re: convert form byte[4] to Int32 while retaining the binary value of the byte array

"Jonathan Mcdougall" <jonathanmcdougall@DELyahoo.ca> wrote in message
news:o0Hxd.22440\$Yb.1199029@weber.videotron.net...
> Howard wrote:
>> <jeff@foundrymusic.com> wrote in message
>>
>>>how do you convert form byte[4] to Int32 while retaining the binary
>>>value of the byte array
>>>

>>
>> As far as I know, neither "Int32" nor "byte" are defined as types in C++.
>> I can *guess* how they're defined, but it's only an eductated guess.
>> What do you mean when you say you want to "retain the binary value"? And
>> in what way do you want to "convert" the value?
>>
>> If what you have is an array of 4 8-bit unsigned char values, and you
>> want to interpret them as a 32-bit signed long, then one way might be to
>> use a pointer, like this:

>
> <snip..>
>
> Int32 convert(Byte b[4])
> {
> return (b[0] << 24) | (b[1] << 16) | (b[2] << 8) | (b[3]);
> }
>
> Byte b[4] = { 1, 2, 3, 4 };
>
> Int32 i = convert(b);
>
>
> Let's not get _that_ picky, people.
>

How do you know that the byte ordering is correct? Maybe b[0] is the LSB!

(And of course you're just assuming the types match. Logical assumption,
but not explicitly stated.)

-Howard

 Alan 12-20-2004 09:09 PM

Re: convert form byte[4] to Int32 while retaining the binary value of the byte array

<jeff@foundrymusic.com> wrote in message news:1103573749.208215.95260@f14g2000cwb.googlegro ups.com...
> how do you convert form byte[4] to Int32 while retaining the binary
> value of the byte array

Your question has nothing to do with C++.
(hint: experiment with a union of these two types)

 Victor Bazarov 12-20-2004 09:13 PM

Re: convert form byte[4] to Int32 while retaining the binary valueof the byte array

Alan wrote:
> <jeff@foundrymusic.com> wrote in message news:1103573749.208215.95260@f14g2000cwb.googlegro ups.com...
>
>>how do you convert form byte[4] to Int32 while retaining the binary
>>value of the byte array

>
>
> Your question has nothing to do with C++.
> (hint: experiment with a union of these two types)

What's a 'union' outside of C++ context? You are contradicting yourself.
If the OP has to look at the union, the question has _everything_ to do
with C++.

Besides, unions are not for conversions between types. They are only to
save memory when storing different types. See more discussions on that
in all known C++ newsgroups.

V

 Alan 12-20-2004 09:43 PM

OT: convert form byte[4] to Int32 while retaining the binary value of the byte array

"Victor Bazarov" <v.Abazarov@comAcast.net> wrote in message news:CfHxd.12489\$Ae.5353@newsread1.dllstx09.us.to. verio.net...
> Alan wrote:
> > <jeff@foundrymusic.com> wrote in message news:1103573749.208215.95260@f14g2000cwb.googlegro ups.com...
> >
> >>how do you convert form byte[4] to Int32 while retaining the binary
> >>value of the byte array

> >
> >
> > Your question has nothing to do with C++.
> > (hint: experiment with a union of these two types)

>
> What's a 'union' outside of C++ context? You are contradicting yourself.

Hardly, they are also used in other languages (as you know), e.g. C

> If the OP has to look at the union, the question has _everything_ to do
> with C++.

see above

> Besides, unions are not for conversions between types.

...but they can be used for that in C

 Howard 12-20-2004 10:00 PM

Re: convert form byte[4] to Int32 while retaining the binary value of the byte array

"Alan" <alan@surfbest.net> wrote in message
news:10sehpr7k08bkc5@news.supernews.com...
>
> "Victor Bazarov" <v.Abazarov@comAcast.net> wrote in message
>> Alan wrote:
>> > <jeff@foundrymusic.com> wrote in message
>> >
>> >>how do you convert form byte[4] to Int32 while retaining the binary
>> >>value of the byte array
>> >
>> >
>> > Your question has nothing to do with C++.
>> > (hint: experiment with a union of these two types)

>>
>> What's a 'union' outside of C++ context? You are contradicting yourself.

>
> Hardly, they are also used in other languages (as you know), e.g. C
>
>> If the OP has to look at the union, the question has _everything_ to do
>> with C++.

>
> see above
>
>> Besides, unions are not for conversions between types.

>
> ..but they can be used for that in C
>
>

The OP asked about doing something in C++ (assumed, since that's where he
posted). You answered in two parts. First, you said his question had
"nothing" to do with C++. Victor rightly asks "why?". In what way does a
accomplish that task in C++, given that that's what we discuss here? Then,
you suggest that somehow the ability to use a union construct to accomplish
the task should be a hint to him. We can only assume that you mean it
should be a hint that the original question has nothing to do with C++. Yet
the union construct does exist in C+, so in what way does it hint that the
OP's question is not about C++? You're suggesting one way to do what he
wants to do (albeit not a good way, IMO), with a construct that is available
in C++, yet saying that this somehow demonstrates that the question you're
proposing an answer to is therefore NOT related to C++. Are you as confused
as I am yet? :-)

-Howard

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